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3 years ago

What best describes the collisions between ideal gas molecules?

1 answer:

5 0

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

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Using the periodic table, complete the table to describe each atom. Type in your answers.

sladkih [1.3K]

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5 0

3 years ago

Solids have: fixed shape O A and B fixed size neither A nor B

Lemur [1.5K]

Answer:

B. A and B

Explanation:

1. Solids have a definite volume, definite size and definite shape

2. The particles present in a solid are very closely packed since the intermolecular forces between them are very strong. The molecules do not move apart.

3. Melting point is the temperature at which solid changes into a liquid.

4. When a solid is heated to the melting point the intermolecular forces are overcome by the energy and the molecules present in it moves from its fixed position to take its liquid state which is called as melting.

8 0

3 years ago

A LA TEMPERATURA DE 35°C, UNA MUESTRA DE DIOXIDO DE CARBONO OCUPA UN VOLUMEN DE 350 ML. ¿Qué CAMBIO DE VOLUMEN SE PRODUCIRA SI L

Kisachek [45]

Answer:

New volume = 150 mL

Explanation:

Initial temperature, T₁ = 35°C

Initial volume, V₁ = 350 mL

We need to find the change in volume when the temperature drops to 15°C.

The relation between the temperature and the volume is given by Charle's law. Let new volume is V₂. It can be given by :

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{350\times 15}{35}\\\\V_2=150\ mL$

So, the new volume is 150 mL.

8 0

3 years ago

An electrochemical cell is constructed such that on one side a pure lead electrode is in contact with a solution containing Pb2+

Ugo [173]

Answer:

-490.7 K

Explanation:

Given:

[Ni^2+]= 0.4 M

[Pb^2+]=0.002 M

∆V= -0.012 V

VNi= -0.250V

VPb= -0.126V

F= 96500 C

R= 8.314 JK-1 mol-1

n= 2

From

T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]

T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]

T= 23213.856(0.112/(-5.298))

T= -490.7 K

4 0

3 years ago

An electron can be added to halogen atom to force a halide ion with

Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

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4 0

2 years ago