Answer:3 moles of Oxygen atoms weigh 48.00 grams.
Explanation:
For the reaction below at dynamic equilibrium, it is true that the rate of the forward reaction equals the rate of the reverse reaction.
Let's consider the following reaction at equilibrium.
N₂(g) + 3 H₂(g) = 2 NH₃(g)
<h3>What is the chemical equilibrium?</h3>
Is a state in which the concentrations of reactants and products are constant and the forward reaction rate and constant reaction rate are equal.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant (K) is the ratio of the concentrations of the products to the concentrations of the reactants, all raised to their stoichiometric coefficients.
Let's consider which statement is true for the equilibrium system.
- The concentration of NH₃ is greater than the concentration of N₂. FALSE. There is not enough information to confirm this, we would need to know the value of K.
- The concentration of NH₃ equals the concentration of N₂. FALSE. There is not enough information to confirm this, we would need to know the value of K.
- The rate of the forward reaction equals the rate of the reverse reaction. TRUE. This is always true for a reaction at equilibrium.
- The rate of the forward reaction is greater than the rate of the reverse reaction. FALSE. At equilibrium, both rates are equal.
For the reaction below at dynamic equilibrium, it is true that the rate of the forward reaction equals the rate of the reverse reaction.
Learn more about chemical equilibrium here: brainly.com/question/5081082
<h3>answer:</h3><h3>es un cambio fisico</h3>
Answer : The O-O bond in 
will be longer than the O-O bond in 
.
Explanation :
In the , the two oxygen atoms are bonded by the single bond and in , the two oxygen atoms are bonded by the double bond.
As we know, the bond strength of double bond is greater than the single bond.
And the relation between the bond strength and bond length is,
That means the higher the strength, the shorter will be the bond length.
Hence, the bond length of single bond will be longer than the double bond.
The structure of given molecule is shown below.
Lewis structure for each of the following N₂O₃ with no N¬N bond is attached below.
Even though pi symmetry occupies the antibonding orbitals of NO, this is unimportant after the dimer forms. A sigma connection exists. The enthalpy of the newly formed sigma bond in the dimer is low because the loss of a particularly distinctive set of single-electron resonance forms that were available for no monomer offset the net gain in bond. When the whole free energy is taken into account, there is no gain because the entropic effects are on the order of 1030kJ/mol, and dimerization is entropically disfavored at G=17kJ/mol. Therefore, any little increase in enthalpy is cancelled out by the loss of entropy.
Learn more about dimer here-
brainly.com/question/17152685
#SPJ4
