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Lana71 [14]
3 years ago
15

Table of ions *chemistry* Please Help me​

Chemistry
1 answer:
Elza [17]3 years ago
7 0

Answer:

See Attached Table

Explanation:

You might be interested in
A. List 3 signs that a chemical reaction occurred.
ioda
A. gas change, color change, and temperature change.

B. color change; one day you wore a ring that wasn't stainless steel in the shower, so the following morning it was rusted.
6 0
3 years ago
Describe Newton's Law of Viscosity and the constitutive behavior of non-Newtonian fluid
CaHeK987 [17]

Answer:

- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers".

- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential.

Explanation:

Hello, here the answers:

- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers" (taken from Kundu, P. K., Cohen, I. M., & Dowling, D. R. (2012). Fluid mechanics.), thus, it means that when you have a fluid with an acting-on-it share stress (an external force which move the fluid), the related velocity gradient (variation or change in velocity) at which the layers are moving are related as:

\pi =-v \frac{du}{dy}

Whereas \pi is the shear stress, v is the viscosity and the differential accounts for the change in the velocity in the arbitrary y coordinate.

- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential, based on:

\pi =-v (\frac{du}{dy})^n

Whereas n accounts for a decreasing or increasing behavior of the shear stress.

Best regards.

8 0
3 years ago
The reaction 2HgO (s)→2Hg (I)+O2 (g) has a percent yield of 50%. You want to produce 100 g of Hg.
nevsk [136]

The mass of HgO needed for the reaction is 216 g

The correct answer to the question is Option C. 216 g

We'll begin by calculating the theoretical yield of Hg.

  • Actual yield of Hg = 100 g
  • Percentage yield = 50%
  • Theoretical yield of Hg =?

Theoretical yield = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield of Hg = 200 g

Finally, we shall determine the mass of HgO needed for the reaction.

2HgO → 2Hg + O₂

Molar mass of HgO = 201 + 16 = 217 g/mol

Mass of HgO from the balanced equation = 2 × 217 = 434 g

Molar mass of Hg = 201 g/mol

Mass of Hg from the balanced equation = 2 × 201 = 402 g

From the balanced equation above,

402 g of Hg were produced from 434 g of HgO.

Therefore

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

Thus, 216 g of HgO is needed for the reaction.

Learn more about stoichiometry:

brainly.com/question/24426334

4 0
2 years ago
Read 2 more answers
a student used 10 mL water instead of 30 mL for extraction of salt from mixture. How may this change the percentage of NaCl extr
Anit [1.1K]
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:

360 g : 1 L = x g : 30 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000 
x = 10.8 g

So, from 30 mL mixture, 10.8 g of NaCl could be extracted.

Let's calculate the same for 10 mL water instead of 30 mL.

360 g : 1 L = x g : 10 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000 
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3

Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water. </span>
5 0
3 years ago
I don’t know how to do it?
kobusy [5.1K]

Kinda blurry can’t see it

5 0
3 years ago
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