Answer:
35%
Explanation:
If two genes are 30 map units apart, 30% of the produced gametes will be recombinant.
A mating between an individual homozygous dominant for both traits (AB/AB) and one homozygous recessive for both traits (ab/ab) is conducted.
The F1 will be heterozygous for both genes: AB/ab.
The F1 progeny is then test-crossed to a homozygous recessive individual:
<h3>AB/ab X ab/ab</h3>
<u>The possible offspring will be:</u>
- Parental (70%): AB/ab and ab/ab
- Recombinant (30%): Ab/ab and aB/ab
Since 30% of all the gametes produced by the F1 individual will be recombinant, 70% will be parental. As there are two types of parental gametes, each of them will have a frequency of 35%.
<u>The offspring that will have a dominant phenotype for both traits has the genotype AB/ab with a proportion of 35%.</u>
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Answer:
:ADFKL
Explanation:;kaDFS": just doing it for the points
Answer: A
Explanation:
Because its the main difference between the 2
