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Otrada [13]
3 years ago
14

There are approximately 7.5×10^18 grains of sand on earth. There are approximately 7×10^27 atoms in a average human body. Are th

ere more grains of sand on earth or atoms in a average human body? How do you know?
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0
There are more atoms in average human body than grains of sand on Earth. We can know it because we can see that atoms' number (7 * 10^27) is being multiplied by much greater number (with 9 zeros more) than grain's number (7.5 * 10^18).
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Calulate the speed distaance=15cm&time=13 sec round to 2 decimal place​
aleksley [76]

Answer:

NOW LETS CONVERT IT INTO SI UNIT THE CM TO METRE . 1CM IS EQUAL TO 10 ^MINUS 3 METRE THEREFORE IF WE CONVERT 15CM TO METRE WE WILL GET 0.015 METRE . now let's multiply GIVE US 0.015*13is equal to 0.0195 now let's rond off to two decimal place it will be 1.6*10to the power minus 2

6 0
4 years ago
A flying disc has a circumference of 75.36 centimeters. What is the area of the flying disc? (Use 3.14 for .)
Hatshy [7]

The area of flying disk is 452.16 square centimeters

Step-by-step explanation:

The disc is in circular shape so we will use the formulas for circle in this question.

Given

Circumference = C = 75.36 centimeters

We have to find the area of the disc for which we have to find the radius first.

Let r be the radius

Then

Circumference is given by:

C=2\pi r

putting the values

75.36 = 2*3.14*r\\75.36 = 6.28r

Dividing both sides by 6.28

\frac{6.28r}{6.28} = \frac{75.36}{6.28}\\r = 12\ cm

The area of circle is given by:

A = \pi r^2

Putting the values

A = 3.14 * (12)^2\\A = 3.14*144\\A =452.16\ cm^2

Hence,

The area of flying disk is 452.16 square centimeters

Keywords: Circle, area

Learn more about circle at:

  • brainly.com/question/12939121
  • brainly.com/question/12941985

#LearnwithBrainly

5 0
3 years ago
Expand each expression and collect like terms -3(2p-3q)
sertanlavr [38]

Answer

(-3 * 2p) - (-3 * 3q)

Step-by-step explanation:

I dunno how to explain it but that's it

7 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
Using the 3 functions below, make the desired transformation(s) to the correct function and describe the transformation(s). Writ
Eduardwww [97]

Answer:

The transformation of g(x) to k(x) consists in a vertical translation. The new equation is k(x) = -12\cdot x-6.

Step-by-step explanation:

Let g(x) = -12\cdot x - 3. We proceed to make the required transformations on g(x), which consists in one vertical translation, 3 units in the -y direction. That is to say:

k(x) = g(x) - 3 (1)

k(x) = (-12\cdot x - 3) - 3

k(x) = -12\cdot x-6

Then, the transformation of g(x) to k(x) consists in a vertical translation. The new equation is k(x) = -12\cdot x-6.

5 0
3 years ago
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