Answer:
The number of combinations will she have to analyze is 10.
Step-by-step explanation:
We know that Boeing currently produces five models of airplanes for commercial sale. The airline that Lauren works for is rapidly expanding and would like to purchase three airplanes of different models to service various routes. We calculate the number of combinations will she have to analyze.

The number of combinations will she have to analyze is 10.
This example is the Symmetric Property.
I hope this helps you!
xo, Leafling
Answer:
a) 

b) From the central limit theorem we know that the distribution for the sample mean
is given by:
c)
Step-by-step explanation:
Let X the random variable the represent the scores for the test analyzed. We know that:

And we select a sample size of 64.
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Part a
For this case the mean and standard error for the sample mean would be given by:


Part b
From the central limit theorem we know that the distribution for the sample mean
is given by:
Part c
For this case we want this probability:

And we can use the z score defined as:

And using this we got:
And using a calculator, excel or the normal standard table we have that:
Increased by 15
past score was x
increased by 15 means he raised to 15+x
it was raised to 83%
therefor
x+15=83
first option is right (and first test was 68%)
Answer:
The answer is 0
Step-by-step explanation:
Have a nice day