Answer:
a. 6.04 m/s^2 (3 sig. fig.) b. T = 30.2 N
Explanation:
a) Assume that the acceleration due to gravity is 9.81 m/s^2 downwards
8x9.81 = (5+8)a
a = 6.04 m/s^2 (3 sig. fig.)
b) Using the results from (a)
T = 5(6.04)
T = 30.2 N
Answer:
Let the weight of the person be W and be located at a distance 'a' from the left scale as shown in the figure
Since the body is in equilibrium we can use equations of statics to analyse the problem.
Taking Sum of Moments about A we have

Taking Sum of Moments about B we have

Solving the above 2 equations for W and 'a' we get

Answer: The momentum is 500.
Explanation: The equation for momentum is p=mv, so you would multiply the mass of the player(50kg) and the speed of the ball(10m/s) to get 500.
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Answer:
Temperature : 92.9 F
Internal Energy change: -2.53 Btu/lbm
Explanation:
As
mh1=mh2
h1=h2
In table A-11 through 13E
p2=120Psi, h1= 41.79 Btu/lbm,
u1=41.49
So T1=90.49 F
P2=20Psi
h2=h1= 41.79 Btu/lbm
T2= -2.43F
u2= 38.96 Btu/lbm
T2-T1 = 92.9 F
u2-u1 = -2.53 Btu/lbm