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Agata [3.3K]
3 years ago
11

How did the astronomy of hipparchus and ptolemy violate the principles of early greek philosophers?

Physics
1 answer:
Mariana [72]3 years ago
8 0

Answer: Hipparchus & Ptolemy believed sun and moon travel around circles with Earth in the middle (geocentric) while Plato and Aristotle believed Perfect unchanging heavens

Explanation: thus hipparchus and ptolemy violate early greek philosophy

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A 1,000 kg car is driving on a 15 m high bridge at 5 m/s. What is the kinetic energy of the car?
yanalaym [24]

Answer:

KE=12,500J

Explanation:

The formula for kinetic energy is:

KE = \frac{1}{2}mv^2

We can plug in the given values into the equation:

KE = \frac{1}{2}*1000kg*(5m/s)^2

KE = 500kg*25m^2/s^2

KE=12,500J

7 0
2 years ago
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7 0
3 years ago
Sandra wanted to see how fast she could kick a soccer ball. She recorded her results below. Unfortunately, she forgot to record
alexira [117]
Kick | Distance (M) | Time (s) | Average Speed

1. 55. 5.0. 11

2. 50. 5.0. 10

3. 20. 3.0. 10
5 0
2 years ago
A steel rod is pulled in tension with a stress that is less than the yield strength. The modulus of elasticity may be calculated
pshichka [43]

Answer:

B. Axial stress divided by axial strain

Explanation:

Elasticity:

It is the tendency of an object to deform along the axis when an opposing force is applied without facing permanent change in shape.

Plasticity:

When an object crosses the elasticity limit, it enters plasticity where the change due to stress is permanent and the object might even break.

Yield strength:

Yield strength is the point of maximum bearable stress that indicates the limit of elasticity.

Our case:

As the stress applied is less than the yield strength, the rod is still in the elasticity state and its modulus can be calculated.

Modulus of Elasticity = Stress along axis/Ratio of change in length to original length

Axial strain is basically the ratio of change in length to original length.

So, Modulus of Elasticity = Axial Stress/ Axial Strain

6 0
3 years ago
A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle θ from the horizontal. The block is ori
vredina [299]

Answer:

f = 0.283

Explanation:

With the given values x=5m and t=2s, the acceleration a of the block must be:

(1) a=\frac{2x}{t^2}

The sum of all forces in the inclined plane must be:

(2) F=ma=sin(\theta) F_{gravity}-F_{friction}=sin(\theta) mg - f cos(\theta) mg

Solving equation2 for the acceleration a:

(3) a=sin(\theta) g - f cos(\theta) g

Using equations 1 and 3 to solve for f:

\frac{2x}{t^2}=sin(\theta) g - f cos(\theta) g\\f=tan(\theta)-\frac{2x}{t^2cos(\theta)g}

4 0
3 years ago
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