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Leya [2.2K]
3 years ago
6

Electromagnetic waves polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis. H

ow much electromagnetic wave intensity is transmitted through the polarizer?
Physics
1 answer:
Digiron [165]3 years ago
6 0

Answer:

there is ZERO TRANSMISSION  through the polarizer.

Explanation:

Given the data in the question;

waves was polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis.

so θ = 90° { aligned with the y-axis }

now, we know that for polarized light going at angle θ to the polarizer;

I = I₀ × cos²θ

Where I₀ is the intensity of unpolarized light.

I is the intensity after polarization.

so we substitute the value of θ

I = I₀ × cos²( 90° )

I = I₀ × 0

I = 0

Therefore, there is ZERO TRANSMISSION  through the polarizer.

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Hurricanes along the Gulf Coastal areas of Texas increase the rate of coastal erosion.
4vir4ik [10]

Answer:

its the last question

Explanation:

Thats because erosion takes away stuff

3 0
3 years ago
2. Using a giant screw, a crew does 650 J of work to drill a hole into a rock.
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3 years ago
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A mountain climber increases their height from 200 meters to 400 meters. What affect will this have on their potential energy?
Yanka [14]

Answer:

At 400 m the potential energy of the mountain climber doubled the initial value.

Explanation:

Given;

initial height of the mountain climber = 200 m

final height of the mountain climber, = 400 m

The potential energy of the mountain climber is calculated as;

Potential energy, P.E = mgh

At 200 m, P.E₁ = mg x 200 = 200mg

At 400 m, P.E₂ = mg x 400 = 400mg

Then, at 400 m, P.E₂ = 2 x 200mg = 2 x P.E₁

Therefore, at 400 m the potential energy of the mountain climber doubled the initial value.

4 0
3 years ago
100 points! please help!!!
IRINA_888 [86]

Answer:

Explanation:

A plane flies due north (90° from east) with a velocity of 100 km/h for 2 hours.

With no wind, it will be 100*2 = 200 km north of its starting point.

But a steady wind blows southeast at 30 km/h at an angle of 315° from due east.

So the wind itself will blow the plane 30*2 = 60km at an angle of 315° from due east.

That is the same as 60*cos315° = 42.43km due east and 60*sin315° = -42.43km north.

Combining, the plane is at 42.43km due east and 200-42.43 = 157.57km due north from its starting point.

7 0
3 years ago
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A daredevil is shot out of a cannon at 31.4 ◦ to the horizontal with an initial speed of 25.9 m/s. A net is positioned a horizon
Tanzania [10]

Answer:

The net should be placed at a height of 8.45 m

Explanation:

In order to calculate the height you have to apply the equations of <em>projectil motion.</em>

For x-axis, the position at a time t is given by:

Xf=Xo +(VoCosα)t (I)

Where Xf is the final position, Xo is the initial position, Vo is the initial speed and t is the time.

For the y-axis, the position at a time t is given by:

Yf=Yo + (VoSinα)t - 0.5gt^{2} (II)

Where Yf is the final position, Yo is the initial position, Vo is the initial speed, t is the time and g is the acceleration of gravity.

For both equations, ∝ is the angle formed by the cannon and the horizontal

The height where the net should be placed in order to catch the daredevil is given by replacing the time when the daredevil will be in the horizontal position of 39.7 m in the equation of position for the y-axis.

So, you have to calculate the time using (I)

Let the system of reference be placed at x=o and y=o

Xf= 0 + 25.9Cos(31,4◦)t

Xf=39.7

39.7=22.1t

Dividing both sides by 22.1 to find the value of t:

t=1.79 seconds

Replacing the time in equation (II) to find the height:

Yf=0 +25.9Sin(31,4◦)(1.79) - 0.5(9.8)1.79^{2}

Yf= 8.45 m

So the height is 8.45 m

4 0
4 years ago
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