Answer:same
Explanation:
Given
ball A initial velocity=3 m/s(upward)
Ball B initial velocity=3 m/s (downward)
Acceleration on both the balls will be acceleration due to gravity which will be downward in direction
Both acceleration is equal
For ball A
maximum height reached is 
After that it starts to move downwards
thus ball have to travel a distance of h_1+h(building height)
so ball A final velocity when it reaches the ground is



For ball b



thus 
Explanation:
Given: uniform electric field E= 82.0 kN/C.
a) charge density σ =ε_0 E.
therefore, 
b)Total charge on each face = σA
q=σA

V = m1 u1 - m2 u2 / m1
v = 0.01 * 500 - 2 * 1.4 / 0.01
v = 220 m/s
Explanation:
KE = KE
½ mv² = ½ mv²
½ (1.88 g) v² = ½ (230.5 g) (58.5 m/s)²
v = 648 m/s