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Alex_Xolod [135]
3 years ago
12

Inside The Atom

Physics
1 answer:
Minchanka [31]3 years ago
3 0
The negatively charge PARTICLE move in the space around the nucleus called the electron cloud or orbital
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stellarik [79]
Wavelength = 1/frequency thus wavelength =1/30000
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If an atom gains or loses a valence electron, the atom becomes a charged particle called a/an_____________.
erica [24]
D i think probably right
5 0
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Read 2 more answers
30 points!
vlada-n [284]

Answer:

Since strong nuclear forces involve only nuclear particles (not electrons, bonds, etc)  items 3 and 4 are eliminated.

Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

Gravitational forces are much much smaller than the weak nuclear force.

6 0
3 years ago
How much energy is needed to change the speed of a 1600 kg sport utility vehicle from 15.0 m/s to 40.0 m/s?
podryga [215]

Answer:

Energy needed = 1100 kJ

Explanation:

Energy needed = Change in kinetic energy

Initial velocity = 15 m/s

Mass, m = 1600 kg

\texttt{Initial kinetic energy = }\frac{1}{2}mv^2=0.5\times 1600\times 15^2=180000J

Final velocity = 40 m/s

\texttt{Final kinetic energy = }\frac{1}{2}mv^2=0.5\times 1600\times 40^2=1280000J

Energy needed = Change in kinetic energy = 1280000-180000 = 1100000J

Energy needed = 1100 kJ

4 0
3 years ago
A car with mass 2.0×10 3 kg traveling east at a speed of 20 m/s collides at an intersection with a2.5×10 3 kg van traveling nort
lys-0071 [83]
When analyzing inelastic collisions, we need to consider the law of conservation of momentum, which states that the total momentum, p, of the closed system is a constant. In the case of inelastic collisions, the momentum of the combined mass after the collision is equal to the sum of the momentum of each of the initial masses.

p1+p2+...=pf

In our case we only have two masses, which makes our problem fairly simple. Lets plug in the formula for momentum; p=mv.

m1v1+m2v2=(m1+m2)vf

To find the velocity of the combined mass we simply rearrange the terms.

vf=m1v1+m2v2m1+m2

Plug in the values given in the problem.

vf=(3.0kg)(1.4m/s)+(2.0kg)(0m/s)03.0kg+2.0kg

vf=.84m/s

7 0
3 years ago
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