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BARSIC [14]
3 years ago
6

Heat is absorbed during which of the following changes?

Physics
2 answers:
leonid [27]3 years ago
7 0

C. Toasting a marshmallow

AfilCa [17]3 years ago
3 0

Answer:

C

Explanation:

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What property of a sound wave increases as the pitch of the sound increases?
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Answer:

Frequency is the property of a sound wave increases as the pitch of the sound increases.

Hope this helps!

Brainliest??

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Kelly carried a box weighing 10 N the 200 meters from his car to his new house.  George took the box from Kelly and carried it u
gladu [14]
While moving box from car to house
<span>W = F * d * cosine (90 degree)
</span>= 10N * 200m * 0 
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While lifing 3m tall flight of stairs
W=F*d*cosine(0 degree)
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4 years ago
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Answer all of them an you will get the brain list
Vlad [161]

Answer:

4. Force = 178.6 Newton.  

5. Acceleration = 2.28 m/s².

6. Force = 178.6 Newton.

Explanation:

4. Given the following data;

Acceleration = 3.8 m/s²

Mass = 47kg

Force = mass * acceleration

Force = 47 * 3.8

<em>Force = 178.6 Newton. </em>

5. Given the following data;

Force = 785N

Mass = 345kg

Acceleration = force/mass

Acceleration = 785/345

<em>Acceleration = 2.28 m/s²</em>

6. Given the following data;

Acceleration = 6m/s²

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<em>Mass = 5.33 kilograms </em>

5 0
3 years ago
Whats a observation?
Mumz [18]
When u look at something and study it
7 0
3 years ago
A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the forc
mel-nik [20]

Answer:

The coefficient of friction is (F/(19.6·m)

Explanation:

The given parameters are;

The force applied to the immovable body = F

The time duration the force acts = t

The time the body spends in motion = 3·t

The acceleration due to gravity, g = 9.8 m/s²

From Newton's second law of motion, we have;

The impulse of the force = F × t = m × Δv₁

Where;

Δv₁ = v₁ - 0 = v₁

The impulse applied by the force of friction, F_f is F_f × (3·t - t) =  F_f × (2·t)

Given that the motion of the object is stopped by the frictional force, we have;

The impulse due to the frictional force = Momentum change = m × Δv₂ = F_f × (2·t)

Where;

Δv₂ = v₂ - 0 = v₂

Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to  act, v₁, we have;

m × Δv₂ = F_f × (2·t) = m × Δv₁ = F × t

∴ F_f × (2·t) = F × t

F_f = F × t/(2·t) = F/2

The coefficient of dynamic friction, \mu _k = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)

\mu _k = (F/(19.6·m)

The coefficient of friction, \mu _k = (F/(19.6·m)

5 0
3 years ago
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