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3 years ago

Two angle measures of a triangle are given what is the third angle measure 57 68 _ 90 40 __ 29 71 _

1 answer:

3 0

$Sum\ of\ angles\ in\ triangle\ is\ 180^{\circ}\\\\
57^{\circ},68^{\circ},x\\
57+68+x=180\\
125+x=180\\
x=55^{\circ}\\\\
90^{\circ},40^{\circ},x\\
90+40+x=180\\
130+x=180\\
x=50^{\circ}\\\\29^{\circ},71^{\circ},x\\
29+71+x=180\\
100+x=180\\x=80^{\circ}$

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2) Last Friday Trevon had $29. Over the weekend he received some money

OverLord2011 [107]

Answer:

12 dollars

Step-by-step explanation:

29+12=41 or 12-49=29

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2 years ago

Evaluate 7j+5-8k when j=0.5 and k=0.25

dlinn [17]

So first you would substitute j and k in the expression.

7(0.5)+5-8(0.25)

3.5+5-2

It would equal 6.5

Hope this helps!

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3 years ago

Read 2 more answers

Answer right = get brainliest

saw5 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

2 years ago

I NEED HELP ON MATH PLS

kicyunya [14]

Answer:

5/2 or 2½ or 2.5

Step-by-step explanation:

20/8 = 2.5

10/4 = 2.5

7 0

3 years ago