(1-sin^2x/cosx)= (sin2x/2sinx)

1 answer:

7 0

Left side:

1-sin²(x) = cos²(x)

1-sin²(x) / cos(x) = cos²(x) / cos(x) = cos(x)

Right side:

sin(2x) = 2 sin(x) cos(x)

sin(2x) / 2 sin(x) = 2 sin(x) cos(x) / 2 sin(x) = cos x 

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Steps to simplifying fractions

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