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4 years ago

5

The six kingdom system was designed

1 answer:

KonstantinChe [14]4 years ago

3 0

Answer:

Prokaryotes is the answer

hope it helped

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How many grams of cl are in 445 g of cacl2?

RideAnS [48]

<span>284 g First, lookup the atomic weights of all the elements involved. Atomic weight of Calcium = 40.078 Atomic weight of Chlorine = 35.453 Now calculate the molar mass of CaCl2 40.078 + 2 * 35.453 = 110.984 Using that molar mass, calculate how many moles of CaCl2 you have. 445 g / 110.984 g/mol = 4.009586967 mol Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms. 4.009586967 * 2 = 8.019173935 And finally, multiply by the atomic weight of chlorine. 8.019173935 * 35.453 = 284.3037735 Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.</span>

7 0

4 years ago

Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. CO + O2 → CO2

liberstina [14]

Answer:

2co + o2 > 2co2

Explanation:

so that is tye answer

3 0

4 years ago

Read 2 more answers

Be sure to answer all parts.

MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol$

Now, molarity of ethanol solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M$

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol$

Now, molarity of sucrose solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L} (1 mL = 0.001 L)\\= 0.94 M$

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol$

Now, molarity of sodium chloride solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M$

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0

3 years ago

What is the volume of water needed to prepare 5000 ml of 0.1 M HCL from a stock solution of4 M

Karo-lina-s [1.5K]

Hey There :

Volume initial = ?

Volume final = 5000 mL

Molarity initial = 4 M

Molarity final = 0.1 M

Therefore :

Mi * Vi = Mf * Vf

4 * vi = 0.1 * 5000

4 vi = 500

Vi = 500 / 4

Vi = 125 mL

Answer A

Hope this helps!

5 0

3 years ago

Fill in the blank <br> ______ is a way to describe matter with numbers and units.

Viktor [21]

Measurements I’m pretty sure

4 0

3 years ago

Read 2 more answers