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AnnZ [28]
3 years ago
15

A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/

final concentration?
Chemistry
2 answers:
galben [10]3 years ago
7 0
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
   1.6 =12×C2
1.6/12=C2
C2     = 0.1333mg/mL
nikdorinn [45]3 years ago
4 0
<span>If the standard solution contains 0.8 mg/mL of a substance and there are 2 mL of the solution, then that quantity contains 0.8*2 = 1.6 mg of the substance. Adding 10mL of water, the new volume will be 2mL + 10mL = 12 mL and there will still be the same 1.6 mg of the substance. Thus the new concentration will be 1.6mg/12mL = 0.133 mg/mL.</span>
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0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
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Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

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Hello can you please help me to solve above fill in the blank questions ​
LiRa [457]

Answer:

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2 years ago
Draw a Lewis structure for HCCl3 . Include all hydrogen atoms and show all unshared pairs and the formal charges, if any. Assume
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Answer:

See answer below

Explanation:

First, let's explain what a Lewis structure is.

A lewis structure in short words is a draw of an atom or molecule showing how the electrons bond with another electrons of atoms, and also shows the unshared pair of electrons, which are the electrons that do not bond in the molecule. In the case of an atom, it shows all the available electrons it has to be shared and bonded with another atom to form a molecule.

With this said, in order to draw the lewis structure we need to know how many electrons the atoms involved have. To know this, we need to write the electronic configuration of the atoms, based on it's atomic number.

In the case of Hydrogen (Z = 1), Carbon (Z = 6) and Cl (Z = 17):

[H] = 1s¹     1 electron available.

[C] = 1s² 2s² 2p²   In this case, we have 4 electrons.

[Cl] = 1s² 2s² 2p⁶ 3s² 3p⁵  In this case, 7 electrons.

Now that we have the configuration, and the available electrons, we need to draw the atoms. The Carbon is the more electronegative atom of them, so, the bonding will be formed based on this atom as the central. So the other atoms will just bond and shared a pair of electron with the carbon. The HCCl₃ can be treated as CH₄, with a tetrahedrical form.

The picture below shows the lewis structure.

Hope this helps

3 0
3 years ago
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