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NemiM [27]
3 years ago
7

Sodium fluoride reacts with hydroxyapatite to give fluorapatite according to the chemical reaction:

Chemistry
1 answer:
Viefleur [7K]3 years ago
5 0
We are given the balanced equation 2NaF + Ca10(PO4)6(OH)2 → Ca10(PO4)6F2 + 2NaOH. The fluorapatite is the product together with sodium hydroxide. The ions involved are (PO4) 3-, Ca 2+ and <span>F-. We add the charges and check if the sum is zero, 2*10+-3*6+-1*2 =0. the zero sum tells that the compound has zero charge or neutral</span>
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Is the water density higher than the aluminum density
posledela
No
Water’s density is 1 g/cm3 and AL is 2700kg/m3
8 0
3 years ago
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

7 0
3 years ago
When 1. 0 l of 0. 00010 m naoh and 1. 0 l of 0. 0014 m mgso4 are mixed, would a precipitate be formed? show work
koban [17]

When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.

<h3>What is a precipitate?</h3>

The precipitate is the solid concentration of a substance that is collected over a solution.

First, we determine the concentration of magnesium and hydroxide

(Mg2+) = 7.00 × 10⁻⁴

(OH−) = 5.00 × 10⁻⁵

Now, we calculate the solubility quotient

Qc = (Mg2+) (OH−) ²

Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²

Qc = 1.75 x 10⁻¹²

The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.

Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.

To learn more about precipitate, refer to the below link:

brainly.com/question/16950193

#SPJ4

5 0
1 year ago
Select the correct answer.
Dmitry [639]

Answer:

A number is right I think

8 0
3 years ago
Read 2 more answers
Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 58 mm Hg. Assume hemoglobin is 50% sat
svetlana [45]

Answer:

0.8988

Explanation:

To calculate the fractional saturation of hemoglobin , the formula used is

YO_2=\frac{(pO_2)^n}{(p50)^n+(pO_2)^n}

now putting the values

YO_2= \frac{58^3}{28^3+58^3}

= \frac{195112}{21952+195112}

=0.8988

Therefore, fractional saturation of hemoglobin= 0.8988

where

YO_2= fractional saturation of hemoglobin

pO_2= partial pressure of oxygen

p50= is the pO_2 at which hemoglobin is 50% saturated

4 0
3 years ago
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