What is 37.09 in expanded form

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Thirty-seven point nine hundredths hope this helps :))

You might be interested in

If x=at^3 and y=bt^2 then find dy/dx

Molodets [167]

Dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
dy/dx = 2b/3at

8 0

3 years ago

A number x is greater than 0. write the word sentence as an inequality

IgorLugansk [536]

9514 1404 393

Answer:

x > 0

Step-by-step explanation:

The only thing that needs translation to symbols is "greater than". Your "word sentence" already uses the symbols x and 0. The symbol for greater than is >. Your inequality is ...

x > 0

8 0

3 years ago

6(m-1) = 3(3m + 2) Show all work

nordsb [41]

Answer:

$\boxed{\sf m = -4}$

Step-by-step explanation:

$\sf Solve \: for \: m: \\ \sf \implies 6 (m - 1) = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \sf \implies 6 m - 6 = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: right \: hand \: side: \\ \sf \implies 6 m - 6 = 9 m + 6 \\ \\ \sf Subtract \: 9 m \: from \: both \: sides: \\ \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\ \\ \sf 6 m - 9 m = -3 m: \\ \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\ \\ \sf 9 m - 9 m = 0: \\ \sf \implies -3 m - 6 = 6 \\ \\ \sf Add \: 6 \: to \: both \: sides: \\ \sf \implies (6 - 6) - 3 m = 6 + 6 \\ \\ \sf 6 - 6 = 0: \\ \sf \implies -3 m = 6 + 6 \\ \\ \sf 6 + 6 = 12: \\ \sf \implies -3 m = 12 \\ \\ \sf Divide \: both \: sides \: of \: -3 m = 12 \: by \: -3: \\ \sf \implies \frac{ - 3m}{ - 3} = \frac{12}{ - 3} \\ \\ \sf \frac{ - 3}{ - 3} = 1: \\ \sf \implies m = \frac{12}{ - 3} \\ \\ \sf - \frac{12}{3} = - 4 : \\ \sf \implies m = - 4$

7 0

3 years ago

Please help fast. <br> Answer the question below:

LenKa [72]

Either SSS or not possible

Mark if correct!

8 0

3 years ago

Try to prove the hypothesis from part B that the sum of a rational and an irrational number is an irrational number.

Maurinko [17]

The next step of your proof is to subtract (a/b) from both sides.

Then you get, x = (m/n) - (a/b)

Since rationals are closed over addition, (m/n) + (-a/b) is a rational number.

Therefore, x (an irrational number) = a rational number <em>This is a false statement which is a contradiction. So, the assumption was incorrect.</em>

Thus, the sum of a rational and irrational number is an irrational number. QED

8 0

3 years ago