Answer:
The coefficient of kinetic friction between the block and the surface is 0.127.
Explanation:
Given that,
The mass of a block, m = 4 kg
The acceleration of the block, a = -1.25 m/s²
We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :
So, the coefficient of kinetic friction between the block and the surface is 0.127.
Answer:
3.5434 eV
Explanation:
For a particle with kinetic energy E and mass m , the wavelength associated is given by the following relation,
E =
Putting the values we get
E =
=1.063 x 10⁻²¹ J
= .0066 eV.
Energy of¹light in terms of eV
= 1244 / 350 = 3.55 eV.
Work function = 3.55 - 0.0066 = 3.5434 eV.
Answer:
B = 0.157 T
Explanation:
Given that,
Length of the solenoid, l = 8 cm = 0.08 m
Number of turns in the wire, N = 2000
Current, I = 5 A
We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :
, N is number of turns per unit length of solenoid.
So,
So, the magnetic field at the center of the solenoid is 0.157 T.