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aniked [119]
3 years ago
11

A beam of light is traveling through a medium at 200,000 km/s. It enters a different medium and speeds up to almost 250,000 km/s

. Finally, it enters a third medium and halts. What were the media the light traveled through, in order? Hurry!!!!!!!!!!!
Physics
2 answers:
Zielflug [23.3K]3 years ago
8 0

Answer:

D

Explanation:

shtirl [24]3 years ago
6 0

Answer

From the question we can see that the in medium  1 speed of light is 200,000 Km/s where as in Medium 2 speed of light is 250,000 km/s.

We can conclude that medium 1 is denser than Medium 2.

In third medium Light speed halts so, the third medium is opaque.

We can say that

Medium 1 can be either water, glass.

Medium 2 will be gas

Medium 3 will be an opaque material.

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ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

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The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

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Where;

k is a constant

k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}

When the new drag force is half of the original drag force;

F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}=  \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}=  0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s

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8 0
3 years ago
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Answer:

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