The description refers to the styloid process or tuberosity. This styloid process is seen in the 5th metatarsal and this area shows the fifth metatarsal's growth plate. This bone is being attached by strong tendon known as the <span>Peroneus brevis tendon.</span>
Answer:
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The objects have different densities
They objects may possess the same volume; however, due to a difference in density, they do not possess the same mass within that volume. This means that they experience a different gravitational force, which causes one to sink and the other to float.
Answer:
<h2>103 Joules</h2>
Explanation:
In this problem we are required to find the potential energy possessed by the television
Given data
mass of television m = 15 kg
height added above the ground, h= 1-0.3 = 0.7 m
acceleration due to gravity g = 9.81 m/s^2
apply the formula for potential energy we have
P.E= m*g*h
P.E = 15*9.81*0.7 = 103 Joules
Answer:
E = 9.4 10⁶ N / C
, The field goes from the inner cylinder to the outside
Explanation:
The best way to work this problem is with Gauss's law
Ф = E. dA = qint / ε₀
We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.
The flow on the faces is zero, since the field goes in the radial direction of the cylinders.
The area of the cylinder is the length of the circle along the length of the cable
dA = 2π dr L
A = 2π r L
They indicate that the distance at which we must calculate the field is
r = 5 R₁
r = 5 1.3
r = 6.5 mm
The radius of the outer shell is
r₂ = 10 R₁
r₂ = 10 1.3
r₂ = 13 mm
r₂ > r
When comparing these two values we see that the field must be calculated between the two housings.
Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is
λ = q / L
Qint = λ L
Let's replace
E 2π r L = λ L /ε₀
E = 1 / 2piε₀ λ / r
Let's calculate
E = 1 / 2pi 8.85 10⁻¹² 3.4 10-12 / 6.5 10-3
E = 9.4 10⁶ N / C
The field goes from the inner cylinder to the outside
