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dusya [7]
2 years ago
14

How can an object overcome static friction?

Physics
1 answer:
larisa86 [58]2 years ago
4 0

Answer:

Applying enough force in one direction to move the object, making kinetic energy.

Explanation:

Simpleness

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A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity
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Answer:

Explanation:

a )

We shall apply the concept of impulse .

Impulse = force x time = change in momentum

= 5 x 4 = 2 ( V - 3 )  , where V is final velocity of the object

20 = 2V - 6

V = 13 m /s

b )

Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )

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- 22 = 2v

v = - 11 m /s

object will move with 11 m /s in opposite direction .

4 0
2 years ago
a 10kg box car rolls at 6m/s and crashes into a 20kg box car that is at rest. After the crash, both cars are stuck together. wha
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Answer:

Their velocity is 0m/s because the first box was only 10 kg and the second box was double the weight

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2 years ago
The air sealed between two panes of glass in some windows helps to _____.
olga_2 [115]
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3 0
3 years ago
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An electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of
Masja [62]

Answer:

magnitude is 1382.59 N/C

Explanation:

Given the data in the question;

The time taken is;

t = x / v

we substitute;

t = ( 2 × 10⁻²) / ( 5.69  × 10⁶ )

t = 3.5149 × 10⁻⁹ s

next, the acceleration is;

a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]

a =  2.42826 × 10¹⁴ m/s²

now, the electric field is;

E = ma / q

we know that;

mass of electron m = 9.11 × 10⁻³¹ kg,

charge of electron q = 1.60 × 10⁻¹⁹ coulomb

we substitute

E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹

E = 2.21214 × 10⁻¹⁶  / 1.60 × 10⁻¹⁹

E = 1.3826 × 10²¹

E = 1382.59 N/C

Therefore, magnitude is 1382.59 N/C  

4 0
2 years ago
What is an object velocity?
Blababa [14]
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