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3 years ago

When an automobile rolls on pavement, the instantaneous center of one of its wheels is located on the wheel axle. True o False

Physics

1 answer:

allsm [11]3 years ago

6 0

Answer:

False

Explanation:

The pavement is the surface is defined as the durable surface material laid down on an area in order to sustain traffic, roadways.

The center of mass will not lie on the wheel axis because the surface is not even or it is not regular surface.

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In a study conducted by a University of Illinois researcher, the football team at Unity High School in Tolono, IL was equipped f

Angelina_Jolie [31]

The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s

<h3>How do I determine the duration (i.e time)?</h3>

Impulse is defined as the change in momentum of an object. It is expressed as:

Impulse = change in momentum

Impulse = final momentum – Initial momentum

Impule = m(v - u)

Impulse = force × time

Impulse = Ft

Thus,

Ft = m(v - u)

Where

F is the force
t is the time
m is the mass
u is the initial velocity
v is the final velocity

Now, we can obtain the duration (i.e time) of the impact. Details below:

Force (F) = 1770 N
Initial velocity = 2.09 m/s
Mass (m) = 4.12 Kg
Final velocity = 0 m/s
Duration (t) =?

Ft = m(v + u) since the collision came to a stop

1770 × t = 4.12 × (0 + 2.09)

1770 × t = 4.12 × 2.09

Divide both sides by 1770

t = (4.12 × 2.09) / 1770

t = 0.005 s

Thus, the duration is 0.005 s

Learn more about time:

brainly.com/question/64749

#SPJ1

6 0

1 year ago

A 920-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,

GrogVix [38]

Answer:21.45 m/s

Explanation:

Given

Mass of sport car=920 kg

Mass of SUV=2300 kg

distance to which both car skid is 2.4 m

coefficient of friction ( $\mu$ )=0.8

Let u be the initial velocity of both car at the starting of skidding

and they finally come to zero velocity

$v^2-u^2=2as$

$acceleration=\mu g=0.8\times 9.8=7.84 m/s^2$

s=2.4 m

$0-(u)^2=2\times (-7.84)\times 2.4$

u=6.13 m/s

so before colliding sport car must be travelling at a speed of

$920\times v=(920+2300)\times 6.13$ (conserving momentum)

v=21.45 m/s

7 0

3 years ago

The points plotted on a graph represent the actual data recorded by an experiment.

aleksandr82 [10.1K]

True. Depending how accurate the graph is plotted

4 0

3 years ago

Read 2 more answers

A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c

GalinKa [24]

The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.

To find the answer, we need to know about the tension.

<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>

Let's draw the free body diagram of the system using the given data.
From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.

$N_x=86.62N$

We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.

$N_y=F_V=mg-Tsin59\\$