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LiRa [457]
3 years ago
9

3. What are the challenges of looking for Dyson spheres?

Physics
2 answers:
S_A_V [24]3 years ago
5 0

1. it is difficult to search for it . Because infrared rays will never penetrate through earth atmosphere.

2. we are unaware of how it looks like and we only know it is red and will glow . A damaged star also looks like this.

3. Dust also makes is hard to detect Dyson spheres . So we will get confused between Dyson sphere and a star surrounded by dust.

Hitman42 [59]3 years ago
5 0

Answer:

A dyson sphere is a hypothetical structure, it is thought of as a way in which an advanced civilization could harness the energy of a star.

Detecting dyson spheres can be a way to find signs of life in space, since they are a sign of a civilization capable of contructing such mega structure.

The problem with detecting them is that dyson spheres surround the star, making it less visible for telescopes on Earth.

But the spheres would radiate infrared radiation, so they could be detected by infrared detectors.

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What is meant by global warming?
pychu [463]

The global warming is the uniform heating of the globe due to the effect of greenhouse gases.

Answer: Option B

<u>Explanation:</u>

Global warming is thus the theory that says that earth is warming up with an increase in temperature over time due to increment in the greenhouse gases.

These are greenhouse gases that are getting increased due to the human activity or say over exploitation of the natural resources. The heating of the globe has caused ozone layer depletion which is also causing warming.

6 0
3 years ago
An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its
Zinaida [17]

Answer:

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force = 12.0v+4.00v^2

Equating both, we have

    784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0

  So v = 12.58 m/s or v = -15.58 m/s ( not possible)

 So terminal velocity of object = 12.58 m/s    

3 0
3 years ago
A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
irinina [24]

288.51 N is  the magnitude of the force that the beam exerts on the hi.nge.

Given

Mass 0f beam = 40 Kg

The horizontal component of the force exerted by the hi_nge on the beam is 86.62 N

Angle between the beam and cable is = 90°

Angle between beam and the horizontal component = 31°

As the system of the beam, hi_nge and cable are in equilibrium.

The magnitude of the force that the beam exerts on the hi_nge can be calculated by -

F =The  horizontal component of force + the vertical component of force  

F = 86.62 N + 40 × 9.8 × sin 31°

F =86.62 N + 201.89 N

F = 288.51 N

Hence, the magnitude of the force that the beam exerts on the hi_nge is 288.51  N.

Learn more about components of forces here brainly.com/question/26446720

#SPJ1

7 0
2 years ago
I've been told that my tension is supposed to be in the mid 40s, but I got seventy three, what did I do wrong?​
Inessa05 [86]

Answer:

you were sopposed to divide

Explanation:

6 0
3 years ago
18. A swimmer steps out of a swimming pool into a light breeze. Why does
OverLord2011 [107]
When the swimmer gets out, the water on her skin begins to evaporate. This process requires takes a lot of energy and that energy comes from the heat of her body. This is similar to when someone sweats. Hope this helps!
6 0
3 years ago
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