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LiRa [457]
3 years ago
9

3. What are the challenges of looking for Dyson spheres?

Physics
2 answers:
S_A_V [24]3 years ago
5 0

1. it is difficult to search for it . Because infrared rays will never penetrate through earth atmosphere.

2. we are unaware of how it looks like and we only know it is red and will glow . A damaged star also looks like this.

3. Dust also makes is hard to detect Dyson spheres . So we will get confused between Dyson sphere and a star surrounded by dust.

Hitman42 [59]3 years ago
5 0

Answer:

A dyson sphere is a hypothetical structure, it is thought of as a way in which an advanced civilization could harness the energy of a star.

Detecting dyson spheres can be a way to find signs of life in space, since they are a sign of a civilization capable of contructing such mega structure.

The problem with detecting them is that dyson spheres surround the star, making it less visible for telescopes on Earth.

But the spheres would radiate infrared radiation, so they could be detected by infrared detectors.

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I need help with this
lisabon 2012 [21]
A. Condensation

Hope this helps!!!
5 0
2 years ago
What happened to the kinetic energy when the velocy of a moving body is doubled?​
dem82 [27]

Answer:

If velocity is doubled, Kinetic Energy increases by 4 times. Kinetic energy of a body is the energy possessed by it, by virtue of its motion, i.e. if the body is moving it will always have kinetic energy.Nov 1, 2018

Explanation:

8 0
2 years ago
Read 2 more answers
Complete the equation???
soldi70 [24.7K]

Here in nuclear reaction we can say that sum of neutrons and protons in reactant side and product side will be same always

Here mass number on the product side is given to us

so sum of mass number is given as

A_1 + A_2 = 265 + 1 = 266

now on the reactant side also the number must be same

A_1' + A_2' = 58 + x

now we will have

58 + x = 266

x = 208

Now number of protons on product side is given as

P_1 + P_2 = 108 + 0

now we also know that atomic number of Fe is 26

so now we will have

P_1' + P_2' = 108

26 + P_2' = 108

P_2' = 82

now the equation is given as

_{26}^{58}Fe + _{82}^{208}Pb = _{108}^{266}Hs + _0^1X

8 0
2 years ago
The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °
sergiy2304 [10]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

<span>V2 = 36.60 in^3</span>

8 0
3 years ago
A gas is compressed from an initial volume of 5.75 L to a final volume of 1.23 L by an external pressure of 1.00 atm. During the
nataly862011 [7]

Answer:

<em>The internal energy change is 330.01 J</em>

Explanation:

Given

v_{1} the initial volume = 5.75 L

v_{2} the final volume = 1.23 L

P_{e} is the external pressure = 1.00 atm

q the heat energy removed = -128 J (since is removed from the system)

expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;

W = -P_{e}ΔV

W = -1.00 x(1.23 - 5.75)

W =  -1.00 x -4.52

W = 4.52 L atm

converting to joules we have

W = 4.52 L atm x 101.33 J/ L atm = 458.01 J

The internal energy change during compression can be calculated thus;

ΔU = q + W

ΔU = -128 J + 458.01 J

ΔU = 330.01 J

Therefore the internal energy change is 330.01 J

8 0
2 years ago
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