Question

33.For a car traveling at a constant speed, the distance driven, d

Answer 1

Given:

$d(t)=80t$

$C(d)=0.09d$

To find:

The value of $C(d(10))$.

Solution:

We have,

$C(d(10))=C(80(10))$           $[\because d(t)=80t]$

$C(d(10))=C(800)$

Now,

$C(d(10))=0.09(800)$           $[\because C(d)=0.09d]$

$C(d(10))=72$

Therefore, the value of $C(d(10))$ is 72.