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kobusy [5.1K]
2 years ago
9

Solve and Answer correctly the question​

Mathematics
1 answer:
never [62]2 years ago
8 0
  • Distance=250m
  • Speed=2m/s

Time:-

  • Distance/Speed
  • 250/2
  • 125s
  • 2min 5s

Time started=6AM

time to reach:-

  • 6+0:02:05
  • 6:02:05 AM
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How do you convert 60 miles per hour is how many feet per second? can iny one help
DiKsa [7]
That's two questions.

The answer to the second question is:  Yes.

The answer to the first question is:

Multiply 60 miles per hour by ' 1 ' a few times.  Use fractions that have
the same thing on top and bottom, since those are always equal to ' 1 '.
Then cancel units if the same unit is on the top and the bottom.
Here's how it goes:

(60 mi/hr) x (5280 ft/mile) x (1hr/3600 sec) = (60 x 5280 / 3600) ft/sec = <u>88 ft/sec</u>

8 0
3 years ago
2. The average age of 25 students is 10years
valentina_108 [34]

Answer:

12.7 years to the nearest tenth.

Step-by-step explanation:

The total of the ages for the 25 students = 10*25 = 250.

For the 30 students it is 15*30 = 450.

The average for the 2 classes = (250 + 450) / (25 + 30)

= 700 / 55

=  12.7 years to the nearest tenth.

4 0
4 years ago
For a singing contest in which 42,000 votes were cast the winner received 3/5 of votes. How many votes did the winner not receiv
DENIUS [597]
3/5 of 42000 is 25200 so the amount of people who did not vote is 16800 because the beginning amount of 42000 subtracted from 25200 gives you the final answer If that's confusing the answer is 16800 votes didn't pick the winner
3 0
4 years ago
Help ASAP Only a few minutes left in class!
evablogger [386]

Answer:

Version "B"

Step-by-step explanation:

All the Version "A"s are higher than Version "B"s.

6 0
3 years ago
How would one prove that:<br> arccos (-x) = π - arccos x for -1 ≤ x ≤ 1
denpristay [2]

Consider \arccos(-x)+\arccos(x), where x \in [-1,1].

This means there exists a \theta \in [0, \pi] such that \cos \theta=x and \cos (\pi -\theta)=-\cos \theta=-x.

Thus, taking the inverse cosine of both of these equations, we get that:

\arccos(x)+\arccos(-x)=\theta+(\pi-\theta)=\pi.

Subtracting arccos(x) from both sides, we get the required result.

4 0
2 years ago
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