I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take

, so that

and we're left with the ODE linear in

:

Now suppose

has a power series expansion



Then the ODE can be written as


![\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%5Cge2%7D%5Cbigg%5Bn%28n-1%29a_n-%28n-1%29a_%7Bn-1%7D%5Cbigg%5Dx%5E%7Bn-2%7D%3D0)
All the coefficients of the series vanish, and setting

in the power series forms for

and

tell us that

and

, so we get the recurrence

We can solve explicitly for

quite easily:

and so on. Continuing in this way we end up with

so that the solution to the ODE is

We also require the solution to satisfy

, which we can do easily by adding and subtracting a constant as needed:
The slope-point form of a line:

The slope-intercept form of a line:

1.

Substitute

2.

Substitute

3.

4.

The answer is 90. you add them all up and divide it by 4
The maximum height is yo<span> = 0</span>
When the projectile is at its maximum height <span> v</span>y = 0.
Note that the maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. :)
Answer:
The name of the solid is cylinder.
Step-by-step explanation:
Draw a circle on top and another one on the bottom. Then draw 2 verticle lines so that your figure is a cylinder