Answer:
The magnitude and direction of the acceleration of the particle is 
Explanation:
Given that,
Mass 
Velocity 
Charge 
Magnetic field 
We need to calculate the acceleration of the particle
Formula of the acceleration is defined as


We need to calculate the value of 


Now, put the all values into the acceleration 's formula


Negative sign shows the opposite direction.
Hence, The magnitude and direction of the acceleration of the particle is 
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:

Then, it means that the net force acting on the test charge has a magnitude of √2F.
The watch hand covers an angular displacement of 2π radians in 60 seconds.
ω = 2π/60
ω = 0.1 rad/s
v = ωr
v = 0.1 x 0.08
v = 8 x 10⁻³ m/s
B- Same force
It’s b because force always acts in equal but opposite pairs.