Answer:
Explanation:The main purpose of astronomical telescope is to make objects from outer space appear as bright, contrasty and large as possible. That defines its three main function: light gathering, resolution and magnification. These are the measure of its efficiency.
Answer:
6666.67 Newtons
Explanation:
The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.
In this case:
- mass= 0.1mg= 1*10^-7 kg
- velocity= 4.00*10^3 m/s
- time= 6.00*10^-8 s
Using velocity and time, acceleration can be calculated as:
Substituting these values into the formula F=ma, the answer is:
- F= (1*10^-7)kg * (6.667*10^10) m/s²
- F= 6666.67 Newtons of force
Answer:
D. Checking to see if the brake fluid is contaminated
Explanation:
The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
<h3>What is flow rate?:</h3>
This is the volume of fluid flowing in a vessel per unit time.
First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.
Using,
- V = F'm................ Equation 1
Where:
- V = Volume of the blood
- F' = Flow rate
- m = mass of blood.
For the Adult,
Given:
Substitute these values into equation 1
For the child,
Given:
Substitute these values into equation 1 also
The amount of blood that flows more through the adult than the child is
- A = 5250-1500
- A = 3750 ml.
Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
Learn more about flow rate here: brainly.com/question/21630019
Answer:
B. The buoyant force on the copper block is greater than the buoyant force on the lead block.
Explanation:
Given;
mass of lead block, m₁ = 200 g = 0.2 kg
mass of copper block, m₂ = 200 g = 0.2 kg
density of water, ρ = 1 g/cm³
density of lead block, ρ₁ = 11.34 g/cm³
density of copper block, ρ₂ = 8.96 g/cm³
The buoyant force on each block is calculated as;

The buoyant force of lead block;

The buoyant force of copper block

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block