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Murljashka [212]

3 years ago

7

archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken

by the arrow to hit the target with a velocity of 90.0 m/s

1 answer:

Cerrena [4.2K]3 years ago

6 0

Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

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A train travelling at 20 m/s has 2 000 000 J of kinetic energy. What is the mass of<br> the train?

Svetlanka [38]

Answer:

<h2>10,000 kg</h2>

Explanation:

The mass of the train can be found by using the formula

$m = \frac{2k}{ {v}^{2} } \\$

k is the kinetic energy

v is the velocity

From the question we have

$m \frac{2(2000000)}{ {20}^{2} } = \frac{4000000}{400} = \frac{40000}{4} \\$

We have the final answer as

<h3>10,000 kg</h3>

Hope this helps you

3 0

3 years ago

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When the voltage is

gizmo_the_mogwai [7]

Explanation:

ask to nirajan shrestha

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7 0

2 years ago

A boy pulls his toy on a smooth horizontal surface with a rope inclined at 60 degrees to the horizontal. If the effective force

lana66690 [7]

I'm thinking that you're supposed to divide. So you would divide 5 into 60 and get 12

6 0

2 years ago

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A block of 200 g is attached to a light spring with a force constant of 5 N / m and freely in a horizontal plane vibrates. The m

Finger [1]

Answer:

m  200 g , T  0.250 s,E 2.00 J

;

2 2 25.1 rad s

T 0.250

 

   

(a)

 

2 2

k m    0.200 kg 25.1 rad s 126 N m

(b)

 

2

2 2 2.00 0.178 mm  200 g , T  0.250 s,E 2.00 J

;

2 2 25.1 rad s

T 0.250

 

   

(a)

 

2 2

k m    0.200 kg 25.1 rad s 126 N m

(b)

 

2

2 2 2.00 0.178 m

Explanation:

That is a reason

8 0

2 years ago

Argon makes up 0.93% by volume of air. Calculate its solubility (in mol/L) in water at 20°C and 1.0 atm. The Henry's law constan

vladimir2022 [97]

Answer:

S= 1.40x10⁻⁵mol/L

Explanation:

The Henry's Law is given by the next expression:

$S = k_{H} \cdot p$ (1)

<em>where S: is the solubility or concentration of Ar in water, $k_{H}$ : is Henry's law constant and p: is the pressure of the Ar </em>

<u>Since the argon is 0.93%, we need to multiply the equation (1) by this percent:</u>

$S = 1.5 \cdot 10^{-3} \frac{mol}{L\cdot atm} \cdot 1.0atm \cdot \frac{0.93}{100} = 1.40 \cdot 10^{-5} \frac{mol}{L}$

Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.

Have a nice day!

8 0

3 years ago