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DENIUS [597]
3 years ago
8

How would planting trees most affect the water cycle? (2 points)

Chemistry
1 answer:
Harrizon [31]3 years ago
6 0
The trees drink water to survive, through their roots, It would help because more condensation would occur.
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What is the charge on an atom after it loses an electron during the formation of a bond?
NARA [144]

Answer:

One positive charge

Explanation:

In a neutral atom, the number of positive and negative particles are equal. This leaves the atom with a net charge of zero, 0.

When the number of protons in an atom is greater than the number of electrons, the atom becomes positively charged. When an atom loses an electron when a bond wants to form, it has a net positive charge.

The number of electrons lost or gained determines the charge.

7 0
3 years ago
Arrange the elements in decreasing order of first ionization energy.
just olya [345]

Answer:

The decreasing order of first ionization energy: Se > Ge > In > Cs

The decreasing order of first ionization energy: x > y > z

Explanation:

Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

<u><em>In the periodic table, down the group, as atomic radius of elements increases, the ionization energy decreases </em></u>

<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

PART (A):

Position of the given elements in the periodic table:

Indium (In): Group 13, period 5

Germanium (Ge): Group 14, period 4

Selenium (Se): Group 16, period 4

Caesium (Cs): Group 1, period 6

Thus, the increasing order of atomic radius: Se < Ge < In < Cs

<u>Therefore, the decreasing order of first ionization energy: </u><u>Se > Ge > In > Cs</u>

PART (B):

Given elements:

element x: radius = 110 pm

element y: radius = 199 pm

element z: radius = 257 pm

Thus, the increasing order of atomic radius: x < y < z

<u>Therefore, the decreasing order of first ionization energy:</u><u> x > y > z</u>

5 0
3 years ago
Approximately how much more energy is released in a 6.5 richter magnitude earthquake than in one with magnitude 5.5?
Elanso [62]
Answer: (C) 30 times

Richter scale is used to determine the magnitude of an earthquake from the arrival time of P and S waves. It determines the total amount of energy released during an earthquake.
If Richter magnitude scale measures 6.5 then it produces 30 times more energy than 1 Richter scale magnitude during an earthquake. The magnitude of an earthquake is plotted on a logarithmic scale from 1 to 9 and increases 10 folds by one magnitude. If 6.5 is the magnitude, it means it is 10 times more than 5.5 magnitude earthquake. Similarly the amount of energy is calculated as 30 folds. So 6.5 magnitude will have 30 folds more energy released than that with 5.5 magnitude earthquake.
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!<br> EXTRA POINTS!!!<br> WILL MARK BRANIEST
Drupady [299]
Cirrus: feathered clouds
Cumulus: fluffy white clouds, dense vertical clouds
Stratus: smooth gray clouds that cover the whole sky
7 0
4 years ago
In an acid-base neutralization reaction 43.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.
timama [110]
The   neutralization reaction between  potassium  hydroxide  and  sulfuric  acid   is  as  follows
2KOH  +  H2SO4 ---> K2SO4  +  2H2O

number  of   moles  of  KOH=  (43.74  x  0.500)/  1000=  0.02187 moles

the  reacting ratio  of  KOH  to H2SO4  is  2:1  therefore  the   moles  of  H2SO4  is  =  0.021187/2=  0.01094 moles

concentration(molarity) = ( 0.01094/50 ) x 1000=  0.2188M
7 0
4 years ago
Read 2 more answers
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