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Zarrin [17]
3 years ago
14

What is the molar mass of calcium bromide?

Chemistry
1 answer:
goblinko [34]3 years ago
7 0
CaBr2 = 40.078 + 79.9 x 2 => 199.878 g/mol
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1. If a person's mass is 56 kg, what is this weight in pounds?<br> 56kg
Natali [406]

Answer:

123lb

Explanation:

lb= 2.2046 kg

56×2.2046= 123lb

3 0
3 years ago
Determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.
Olenka [21]

As per Ideal gas equation, molar mass of the gas is 5.032 g/mo

We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:

Volume (V) = 1.6 L

Temperature (T) = 287 K

Pressure (P) = 0.92 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

According to Ideal gas equation , PV = nRT

0.92 × 1.6 = n × 0.0821 × 287

1.472 = n × 23.5627

Divide by 23.5627

n = 1.176 / 23.5627

n = 0.0624 mole

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 0.314 g

Number of mole = 0.0624 mole

Mole = \frac{mass}{molar mass}

0.0624 = \frac{0.314}{molar mass}

Cross multiply

0.0624 × molar mass of gas = 0.314

Divide by 0.0624

Molar mass of gas =  \frac{0.314}{0.0624}

Molar mass of gas = 5.032 g/mo

Therefore the Molar mass of gas is 5.032 g/mo

Learn more about  Ideal gas equation here:

brainly.com/question/3637553

#SPJ1

8 0
2 years ago
How would you prepare 100.0 mL of 0.400 M CaCl2 from a stock solution of 2.00 M CaCl2?
Sever21 [200]

Answer:

Measure 20mL of the stock

Explanation:

All we need to do is to find the volume of the stock solution needed. This is illustrated below:

C1 = 2M

V1 =?

C2 = 0.400 M

V2 = 100mL

C1V1 = C2V2

2 x V1 = 0.4 x 100

Divide both side by 2

V1 = ( 0.4 x 100) /2

V1 = 20mL

Therefore, to prepare the solution, we will measure 20mL of the stock solution and make it up to the 100mL mark.

4 0
3 years ago
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What coefficients do you need to balance the following equation Rb, P, Rb3P
expeople1 [14]

Answer:

3,1,1 would work

Explanation:

4 0
3 years ago
Can you please help me on my Chemistry homework.
Yanka [14]

Answer: Hold on, our servers are swamped. Wait for your answer to fully load.

Explanation: i took the tet

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