Answer:
The mechanism for both of these reactions is very similar to the mechanism for the reduction of acyl chlorides by LATB—H. The first step is an acid‐base reaction between an unshared electron pair on oxygen or nitrogen with the aluminum atom of the DIBAL—H. The second step is the transfer of a hydride ion from the DIBAL—H to the carbon atom of the carbonyl or nitrile group. The last step is the hydrolysis of the aluminum complex to form the aldehyde
Explanation:
Ozonolysis of alkenes
Alkenes in which the carbon(s) of the double bond possess one or more hydrogen atoms react with ozone (O 3) to generate aldehydes. The reaction of propene with ozone to form acetaldehyde and formaldehyde illustrates this method of preparation.
Hydroboration of terminal alkynes
Terminal alkynes react rapidly with borane to produce an intermediate compound that is easily oxidized to an aldehyde. For example, you can produce pentenal by reacting pentyne with borane and oxidizing the resulting intermediate with aqueous hydrogen peroxide.
Answer:
THE ANSWER IS : C experimental results are not reliable if they are not repeatable
Explanation:
I just did this question
Answer:
<h2>Sodium Sulfide</h2>
Explanation:
Na2s means two sodium atoms and 1 sulfur atom. Sodium Sulfide is the answer. There isn't really a way to explain further.
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Answer:
Molecular Formula: C6H11NaO2
Parent Compound: CID 8892 (Hexanoic acid)
Explanation:
When a mixture of 1−hexanol and hexanoic acid in diethyl ether is shaken with an aqueous NaHCO 3 solution, Hexanoic acid will react with NaHCO 3 to form sodium hexanoate.
CH 3 −CH 2 −CH 2 −CH 2 −CH 2−COOH+NaHCO 3→CH 3−(CH 2 ) 4 −COONa+H 2 O+CO 2