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3 years ago

10

What method of heat transfer can occur in a vaccum

1 answer:

vlada-n [284]3 years ago

5 0

In vacuum heat transfer occurs through radiation

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A neutral atom has 1 valence electron and its atomic mass is 39. How many

uranmaximum [27]

Answer: I think probaly wrong so probaly dont

listen to me

Explanation:

5 0

3 years ago

Which pair of atoms has the highest electronegativity difference?

rjkz [21]

The B. Ca-F pair has the greatest electronegativity difference.

Electronegativities <em>increase from the lower left to the upper right</em> in the Periodic Table.

Ca is closest to the lower left, and F is in the upper right, so the Ca-F bond has the greatest electronegativity difference.

4 0

4 years ago

Read 2 more answers

In terms of chemical bonds and electrons, what kinds of changes occur between atoms when substances undergo chemical reactions?

STALIN [3.7K]

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.
<span>www.middleschoolchemistry.com/lessonplans/chapter6/lesson1</span>

8 0

4 years ago

A large balloon contains 233 L of neon at 22.0C and 760. Torr. If the balloon ascends to an altitude where the temperature is -

shepuryov [24]

Answer: The volume in the balloon at the higher altitude is 260 L

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 760 torr

$P_2$ = final pressure of gas = 511 torr

$V_1$ = initial volume of gas = 233 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $22.0^0C=(22.0+273)K=295K$

$T_2$ = final temperature of gas = $-52.0^0C=(-52.0+273)K=221K$

Now put all the given values in the above equation, we get:

$\frac{760\times 233}{295}=\frac{511\times V_2}{221}$

$V_2=260L$

The volume in the balloon at the higher altitude is 260 L

3 0

3 years ago

A 4.10 −g sample of a mixture of CaO and BaO is placed in a 1.00-L vessel containing CO2 gas at a pressure of 735 torr and a tem

insens350 [35]

Answer:

The mass % of CaO is 9.37%%

Explanation:

<u>Step 1: </u>Data given

Mass of the mixture = 4.10 grams

Volume of the vessel = 1.00 L

The vessel contains CO2 with a pressure of 735 torr and temperature = 26 °C

The pressure of the remaining CO2 is 155 torr

<u>Step 2:</u> The balanced equation

CaO/BaO + CO2 → CaCO3 /BaCO3

.

<u>Step 3</u>: Calculate moles CO2 (via ideal gas law)

CO2 is the only gas, this means the drop in the pressure is caused by CO2

Δp = 735 torr - 155 torr = 580 torr

580 torr = 0.763 atm

n = PV/RT = (0.763atm)(1.00L) / (0.08206 L*atm/K*mol)(299) = 0.0391 moles CO2 initial

moles reacted = 0.0311 moles CO2

Step 4: Calculate mass of CaO and BaO

Let's suppose x = mass of CaO. Then mass of BaO = 4.10-x.

In the balanced equation, we notice the mole ratio of CaO/BaO with CO2 is 1:1. This means the number of moles CaO + moles BaO = Number of moles CO2

moles CaO + moles BaO = moles CO2

x/56.08 + (4.10-x)/153.33 = 0.0311

56.08 (x/56.08 + (4.10-x)/153.33) = (56.08)(0.0311)

x + (0.366)(4.10-x) = 1.744

x + 1.5006 - 0.366x = 1.744

0.634x = 0.2434

x = 0.384g CaO

4.1-x = g BaO = 3.716 grams

%CaO = (0.384 g / 4.10 g) x 100 = 9.366% ≈ 9.37

The mass % of CaO is 9.37%

7 0

4 years ago