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Inessa05 [86]
4 years ago
6

Name two elements that have the same properties as calcium

Chemistry
2 answers:
evablogger [386]4 years ago
4 0

<u>Answer:</u> The two elements having same properties as calcium are magnesium and strontium.

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Calcium is the 20th element present in Group 2 and Period 4 of the periodic table. The electronic configuration of this element is 1s^22s^22p^63s^23p^64s^2

The number of valence electrons in Calcium are 2.

The elements having similar chemical properties as of calcium will be magnesium and strontium because they both have the same valence electrons that is 2.

Hence, the two elements having same properties as calcium are magnesium and strontium.

adoni [48]4 years ago
3 0
Magnesium, strontium and barium are a few of the elements that have the same properties as calcium. elements found in group 2 of the periodic table have similar properties to it.
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First, find the volume the solution needs to be diluted to in order to have the desired molarity:
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M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
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V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
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