Answer:
(a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.
Explanation:
Given that,
Mass of block =1.60 kg
Force constant = 315 N/m
Speed = 13.0 m/s
(a). We need to calculate the amplitude of the motion
Using conservation of energy
Put the value into the relation
(b). We need to calculate the block’s maximum acceleration
Using formula of acceleration
Put the value into the formula
(c). We need to calculate the maximum force the spring exerts on the block
Using formula of force
Put the value into the formula
Hence, (a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.
Breaker D cuz it says 18 and that’s the highest temp
Answer:
Current in circuit = 2 amp
Explanation:
Given:
Voltage of battery = 10 V
First Resistance R1 = 1 ohm
Second Resistance R2 = 4 ohm
Resistor connected in series
Find:
Current in circuit
Computation;
Resistor connected in series
So,
Total resistance R = First Resistance R1 + Second Resistance R2
Total resistance R = 1 ohm + 4 ohm
Total resistance R = 5 ohm
Current in circuit = V / R
Current in circuit = 10 / 5
Current in circuit = 2 amp
Gravity is a force acting on a object
Answer:
<h2>0.39m/s^2</h2>
Explanation:
Step one:
given data
mass m= 300kg
applied force F= 1000N
coefficient of friction μ= 0.3
Step two:
The net force Fn= applied force-friction force
Fn=F-F1
F1= limiting force
F1=μ*m*g
F1=0.3*300*9.81
F1=882.9N
the Net force= 1000-882.9
Fn=117.1N
Step three:
we know that
F=ma
Fnet=ma
a= Fnet/m
a=117.1/300
a=0.39m/s^2
