All categories

3 years ago

How is a crowbar used to remove the top of a box change the direction of the force

1 answer:

7 0

The crowbar is placed under a small edge under the top of the box. The crowbar will send the box lid flying from the opposite direction that the crowbar is placed. Please give Brainlest if you understand.

You might be interested in

Suppose that all the dislocations in 4700 mm3 of crystal were somehow removed and linked end to end. Given 1 m = 0.0006214 mile,

san4es73 [151]

Answer:

a. The required chain length = 292.1 miles

b. Length of the required chain = $29.2*10^6miles$

Explanation:

Cold work is the work performed on a material at a temperature below the re-crystallization temperature of the material.

Dislocation density is the measure of the total number of dislocation of a crystalline material of unit volume.

Deformation is the process of change in an objects shape due to the application of force

a. In order to find the length of required chain for the given dislocation density

length of required chain = total length of dislocation line = dislocation density * volume

where dislocation density = $10^5mm^{-2}$

and volume is given as = $4700mm^3$

$=10^5*4700mm(\frac{1mi}{1.609*10^6mm} )=292.1miles$

b. To find the length of required chain

length of required chain = dislocation density * volume

where dislocation density = $10^{10}mm^{-2}$

we substitute in the equation above to get

$=10^{10}mm^{-2}*4700mm^3\\=47*10^{12}mm*(\frac{1mile}{1.609*10^6mm} )=29.2*10^{6}miles$

6 0

3 years ago

Suppose two waves collide, and the temporary combined wave that results is smaller than the original waves. what term best descr

BlackZzzverrR [31]

The collision of the two waves would bring force and that would make the new wave smaller

3 0

3 years ago

A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular t

Lisa [10]

Explanation:

Let us assume that piece 1 is $m_{1}$ is facing west side. And, piece 2 is $m_{2}$ facing south side.

Let $m_{1} \text{and} m_{2}$ = m and $m_{3}$ = 2m. Hence,

$2mv_{3y} = m(21)$

$v_{3y} = \frac{21}{2}$

= 10.5 m/s

$2mv_{3x} = m(21)$

$v_{3x} = \frac{21}{2}$

= 10.5 m/s

$v_{3} = \sqrt{v^{2}_{3x} + v^{2}_{3y}}$

= $\sqrt{(10.5)^{2} + (10.5)^{2}}$

= 14.84 m/s

or, = 15 m/s

Hence, the speed of the third piece is 15 m/s.

Now, we will find the angle as follows.

$\theta = tan^{-1} (\frac{v_{3y}}{v_{3x}})$

= $tan^{-1}(\frac{10.5}{10.5})$

= $tan^{-1} (45^{o})$

= $45^{o}$

Therefore, the direction of the third piece (degrees north of east) is north of east.

5 0

3 years ago

Shalnov [3]

Answer:

No.

Explanation:

Given the following :

Velocity (V) of ball = 5m/s

Radius = 1m

Can the ball reach the highest point of the circular track

of radius 1.0 m?

The highest point in the track could be considered as the diameter of the circle :

Radius = diameter / 2;

Diameter = (2 * Radius) = (2*1) = 2

Maximum height which the ball can reach :

Using the relation :

Kinetic Energy = Potential Energy

0.5mv^2 = mgh

0.5v^2 = gh

0.5(5^2) = 9.8h

0.5 * 25 = 9.8h

12.5 = 9.8h

h = 12.5 / 9.8

h = 1.2755

h = 1.26m

Therefore maximum height which can be reached is 1.26m.

Since h < Diameter

7 0

3 years ago

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of

alexandr1967 [171]

Answer:

The value is $h = 11930 \ m$

Explanation:

From the question we are told that

The temperature is $T = 300 \ K$

Generally the root mean square speed of the oxygen molecules is mathematically represented as

$v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }$

Here R is the gas constant with a value $R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}$

M is the molar mass of oxygen molecule with value $M = 0.032 \ kg /mol$

$\frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h$

=> $h = 11930 \ m$

4 0

3 years ago