So when it comes to Gravitational Potential Energy the higher an object of mass is the more energy it has as the equation for EPG is = MGH so the M is Mass of the object , the G is the gravitational constant which on earth is roughly 9.8 m/s and the H is the height of the object. So the greater the H value is the more energy you'll have. An example would be using your 30kg mass say at a height of 10 meters would have the EPG of 2940 Joules of energy since EPG= MGH so EPG= (30)(9.8)(10) . Now if the object was at a height of 20 meters the EPG would be greater as EPG=(30)(9.8)(20) which would be 5880 joules of energy
The answer to the question is False i.e A phoneme is not the largest unit of sound.
EXPLANATION:
Phoneme is related to linguistics or the sound system of language which is the language specific.
It is defined as the smallest contrastive unit of sound in speech which can give a distinct meaning. It distinguishes one word from the other word in a unique way .When we put all the phonemes of a particular word, the corresponding word is formed .
<span>Yes, it's possible to hoist the child up.
Let's first determine the maximum amount of pull that the woman can exert. That will be the simple product of her weight and the coefficient of static friction with her shoes and the ground. So
0.8 * 190 = 152.
So far, so good, since 152 is greater than the boy's 80 lbs. But the cable rubs at the cliff edge and that means that the lady has to pull harder. Let's see how much harder.
There will be 80 lbs of tension on the cable, pressing against the cliff edge. So let's multiply by the coefficient of friction to get how much that is
0.2 * 80 = 16
So friction will take 16 lbs of effort to overcome. So the lady needs to pull with 80 + 16 = 96 lbs of force to move the boy. And since we've determined earlier that she can pull with up to 152 lbs of force, she can easily hoist the child up.</span>
Answer: I believe farther. Correct me if I am wrong
Explanation:
Answer:
0.82 m
Explanation:
The ball is in free fall - uniform accelerated motion with constant acceleration downward, 
(acceleration of gravity). So we can use the following suvat equation to solve the problem:
where
v is the final velocity
u = 4 m/s is the initial velocity
a is the acceleration
s is the displacement
At the maximum displacement, v = 0 (the velocity becomes zero). Substituting and solving for s, we find:
