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2 years ago

Help me please I give thanks

2 answers:

8 0

If it helps, I would draw a diagram/picture first and label what you do know. The formula for the area of a trapezoid is A=(a+b)÷2xh a and b are the two bases, h is the height. So let's substitute that into the equation: 95 = [(8+10) ÷ 2] x height. Sorry for all the brackets, computers like this arent really meant for maths.... Now you want to rearrange the equation to make height the subject, like this.... Height = 95 ÷ [(8+10) ÷ 2]. It's easier if we work out the brackets first. 8 +10, quite simple, 18, divided by 2 = 9. Height = 95 ÷ 9 = 10.56 (rounded to two decimal places). To check, use the original formula for area with all the values substituted in: 95 = 9 x 10.56 which is.... 95. Unfortunately I can't change is to the units you need because I live in the UK and don't work in feet and the inches but hopefully you can change 10.5555556 feet into what you need (I think it's 10 foot 7 inches). Sorry for the long answer.

Ede4ka [16]2 years ago

6 0

Use the formula of the area of a trapezoid.
A=(B+b)·h/2
B=10ft
b=8 ft
A=95 ft
(10+8)·h/2=95|·2
18h=95·2
18h=190
h=190:18
h=10,5 ft

Answer: 10,5 ft

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a right triangle has legs of length 3x m and 4x m and hypotenuse of length 75 m. find the lengths of the legs of the triangle

just olya [345]

It is a 3-4-5 right triangle

leg1 := 3x, leg2:=4x, hypotenuse:=5x

given hypotenuse = 75m
=> 5x=75
So, x= 75÷5 = 15
Therefore, leg1 = 3(15) = 45m.
leg2= 4(15) = 60m.

4 0

2 years ago

2x+3y=-12 2x+t=-16 X=. Y= Help plz

8090 [49]

To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.

Answer:

x = -9

y = 2

Step-by-step explanation:

Solve the system:

2x + 3y = -12 [1]

2x + y = -16 [2]

Subtracting [1] and [2]:

3y - y = -12 + 16

2y = 4

y = 4/2 = 2

From [1]:

2x + 3(2) = -12

2x + 6 = -12

2x = -18

x = -18/2 = -9

Solution:

x = -9

y = 2

8 0

2 years ago

Which of the following tables shows a rate greater than 1 kilometer per hour

LenKa [72]

Answer:

it is C

Step-by-step explanation:

4 0

2 years ago

What is 2x-5/3=7? Plz help!

ki77a [65]

Hello! And thank you for your question!

First add 5/3 to both sides:

2x = 7 + 5/3

Then simplify 7 + 5/3:

2x = 26/3

Then divide both sides by 2:

x = 26/3 over 2

After that simplify 26/3/2:

x = 26 over 3 x 2

Simplify 3 x 2:

x = 26/6

Simplify:

x = 13/3 or 4 1/3

Final Answer:

x = 13/3 or 4 1/3

5 0

2 years ago

Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S

Sophie [7]

Answer:

Recall that a relation is an equivalence relation if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

Reflexive: We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that $A=J^{-1}AJ$ . Thus, A↔A.

Symmetric: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that $A=P^{-1}BP$ . In this equality we can perform a right multiplication by $P^{-1}$ and obtain $AP^{-1} =P^{-1}B$ . Then, in the obtained equality we perform a left multiplication by P and get $PAP^{-1} =B$ . If we write $Q=P^{-1}$ and $Q^{-1} = P$ we have $B = Q^{-1}AQ$ . Thus, B↔A.

Transitive: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have $A=P^{-1}BP$ and from B↔C we have $B=Q^{-1}CQ$ . Now, if we substitute the last equality into the first one we get

$A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP)$ .

Recall that if P and Q are invertible, then QP is invertible and $(QP)^{-1}=P^{-1}Q^{-1}$ . So, if we denote R=QP we obtained that

$A=R^{-1}CR$ . Hence, A↔C.

Therefore, the relation is an equivalence relation.

4 0

2 years ago