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Vikki [24]
3 years ago
7

what is thelenght and width of a rectangle that had an area of 18 square Ubuntu and a perimeter of 18 units ?

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

Length=6

Width=3

Step-by-step explanation:

Area:L*W

Area= 6*3=18

Perimeter: 2 (L+W)

Perimeter= 2 (6+3)= 12+6=18

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A party mix has 8 ounces of pretzels,3 ounces of mini marshmallows, and 6 ounces of nuts. how many ounces of nuts are there for
Mars2501 [29]
Hey! Sorry that no one has answered your question in 4 days. But anyways, to do this, we need to simplify the problem a little. The mini marshmallows are unneeded, so we don't even have to think about them. Do do this, all you need to do is divide the 6 ounces of nuts and the 8 ounces of pretzels, or 6 / 8, to get 0.75.
3 0
3 years ago
What value of x makes this statement true?<br><br> 3x = 2x+12
saul85 [17]

Answer:

x=12

Step-by-step explanation:

3x=2x+12

3x-2x=12

x=12

4 0
3 years ago
Read 2 more answers
A box with a square base and open top must have a volume of 97556 c m 3 cm3 . We wish to find the dimensions of the box that min
Kipish [7]

Answer:

S(x)  =  x²  +  390224/x

Step-by-step explanation:

Volume of the open box  =   V  = 97556 cm³

Material needed:

Let´s call x the side of the square base then  the  area of the base is

A(b) = x²

For the sides of the box, we have 4 sides each one with area of x*h

where h is the height of the box

The volume of the box    V(b) = 97556 = x²*h   then    h  =  97556/x²

S(x,h) = x²  +  4*x*h*

The surface area of the box as function of x is:

S(x)  =  x²  + 4*x*97556/x²

S(x)  =  x²  +  390224/x

6 0
3 years ago
Question 1 of 10
Natali5045456 [20]
I believe it’s letter c if it’s saying 2/4 and reduce down to 1/2
6 0
2 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
3 years ago
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