Find the average value of y equals the square root of the quantity 64 minus x squared, on its domain.
1 answer:
Answer:
2π ≈ 6.283
Step-by-step explanation:
The average value of the function is the area under it, divided by the base. This function describes a semicircle of radius 8, so its area is ...
A = 1/2πr² = 1/2π·8² = 32π
The width of the base is the diameter of the semicircle, so is 16. Then the average value is ...
32π/16 = 2π . . . . . average value of y
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Answer:
Options (A) and (C)
Step-by-step explanation:
From table attached,
Let the equation of a linear equation that represents the input-output values in the table is,
y - y' = m(x - x')
Where (x', y') is a point lying on the graph.
And m = slope of the line passing through two points and
m =
Slope of the line passing through (0, 11) and (1, 5) will be,
m =
m = -6
Therefore, equation of the line passing through (0, 11) and slope = -6 will be,
y - 11 = -6(x - 0)
Equation of a line passing through (1, 5) and slope = -6 will be,
y - 5 = -6(x - 1)
Equation of a line passing through (2, -1) and slope = -6 will be,
y + 1 = -6(x - 2)
Equation of a line passing through (3, -7) and slope = -6 will be,
y + 7 = -6(x - 3)
Therefore, Options (A) and (C) are the correct options.