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3 years ago

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FIND THE SLOPE OF THE LINE THAT PASSES THROUGH EACH PAIR OF GIVEN POINTS(please show work). (2,4) and (-3,1)

1 answer:

Nataliya [291]3 years ago

4 0

$m= \frac{y_{2} - y_{1} }{ x_{2} - x_{1} } = \\m= \frac{(4)-(1)}{(2)-(-3)} = \\ m= \frac{3}{5}$

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What means the same as 6 x 5?<br> 65<br> 5 + 5 + 5 + 5 + 5<br> 6+6+6+6+6<br> I need an answer

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2 years ago

Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are .

Evgen [1.6K]

QUESTION 1

The point C(3.6, -0.4) divides AB in the ratio 3 : 2.

The coordinates of A are (-6, 5).

Let the coordinates of B be $(x_2,y_2)$

We use the formula:

$x=\frac{mx_2+nx_1}{m+n}$ to determine the x-coordinate of B.

We substitute the known values to obtain:

$3.6=\frac{3x_2+2(-6)}{3+2}$

$3.6=\frac{3x_2-12)}{5}$

$3.6\times 5=3x_2-12$

$18=3x_2-12$

$18+12=3x_2$

$30=3x_2$

This implies that:

$x_2=10$

We also use the formula:

$y=\frac{my_2+ny_1}{m+n}$ to find the y-coordinate.

$-0.4=\frac{3y_2+2(5)}{3+2}$

$-0.4=\frac{3y_2+10}{5}$

$-0.4\times 5=3y_2+10$

$-2-10=3y_2$

$-12=3y_2$

$-4=y_2$

The coordinates of B are (10,-4)

QUESTION 2.

If point D divides CD in the ratio 4 : 5.

Then the coordinates of D are:

$(\frac{4(10)+5(3.6)}{4+5}, \frac{4(-4)+5(-0.4)}{4+5})$

$(\frac{58}{9}, \frac{-18}{9})$

The coordinates of D are $(\frac{58}{9}, -2)$

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3 years ago