The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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Answer:
(2x-4)-(6-8x)
2x-4-6+8x
2x-10+8x
10x-10
Step-by-step explanation:
The question's asking the difference between 2 binomial polynomials.
1. To subtract them, you must use the distributive property to distribute the minus sign on the terms in the second polynomial.
2. Combine like terms. -4-6=-10, 2x+8x=10
<u>Answer is 10x-10</u>
Answer: No, an integer is a whole number that can be either negative or positive :)
Step-by-step explanation:
Answer:
Ok is there options? Because that will make it easy but I dont think your supposed to ask for help on a district test
