Question

A car is traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds what is it’s acceleration

Answer 1

Hello!

A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. What is it's acceleration ?

We have the following data:

Vi (initial velocity) = 10 m/s (starts)

Vf (final velocity) = 0 m/s (stop)

t (time) = 20 s

a (acceleration) = ? (in m/s²)

We apply the data to the formula of the hourly function of the velocity, let us see:

$V_f = V_i + a*t$

$0 = 10 + a*20$

$- 10 = 20\:a$

$20\:a = - 10$

$a = \dfrac{-1\diagup\!\!\!\!0}{2\diagup\!\!\!\!0}$

$\boxed{\boxed{a = - 0.5\:m/s^2}}\Longrightarrow(the\:car\:slows\:down)\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:  

The acceleration is -0.5 m/s² (decelerate)  

________________________________

$\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}$

Answer 2

Answer:

-0.5 m/s

Explanation:

given:

u (initial velocity) = 10 m/s

v (Final velocity) = 0 m/s (because it is given that it comes to a complete stop)

t (time taken) = 20 s

therefore,

acceleration = v - u / t

a = 0 - 10 / 20  

a = -10 / 20

a =  -1/2

a = -0.5

There is a acceleration of -0.5 m/s