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kobusy [5.1K]
3 years ago
5

Type the correct answer in the box. Round your answer to the nearest whole number. The mass of Venus is 4.87 × 1024 kilograms, a

nd the mass of Jupiter is 1,898 × 1024 kilograms. The mass of Jupiter is about times the mass of Venus.
Physics
1 answer:
den301095 [7]3 years ago
7 0

The gravitational effect on other bodies determines the weight (or the mass) of a planet. We must somehow measure the strength of its "tug" on another object in order to use gravity to find the mass of a planet. We can harness Newton's equations to deduce what the mass of the planet must be through observing the time it takes for the satellite to orbit its primary planet.

 

Given:

 

Mass of Venus = 4.87 x 1024 kg

= 4986.88

Mass of Jupiter = 1.898 x 1024 kg

= 1943.552

Mass of Jupiter compared to mass of Venus

 

1943.552 / 4986.88

= 0.3897330595482546

= 0.3897330595482546 x 100%

= 38.97%

 

So, in this problem, <span>the mass of Jupiter is about 0.39 times the mass of Venus.</span>

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A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

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where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
You push a cart with mass 15 kg forward , giving it an acceleration of 3 m/s ^ 2 . How much force did you apply ? O A. 0.2N O B.
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Answer: force = mass x accelegation

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7 0
3 years ago
Read 2 more answers
weegy a 7.5kg block is placed on a table. if its bottom surface area is 0.6m2 , how much pressure does the block exert on the ta
Lesechka [4]

The pressure exerted by the block on the table is given by:

p=\frac{W}{A}

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The weight of the box is: W=mg=(7.5 kg)(9.81 m/s^2)=73.6 N

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Answer:

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Explanation:

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Leona [35]

Answer:

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Explanation:

PLEASE DO NOT ASK SUCH QUESTIONS AGAIN.

Just kidding :)

5 0
3 years ago
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