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Hatshy [7]
3 years ago
15

A dog is 60m away while moving at constant velocity of 10m/s towards you. Where is the dog after 4 seconds?

Physics
2 answers:
Kitty [74]3 years ago
6 0
The dog is 20m away.
if the dog moves 10m/s, multiply 10 by 4, subtract 40 from 60. 20
evablogger [386]3 years ago
4 0
20m away

the dog was 60m away from. you subtract 40m since it is 10m/s x 4 seconds
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a) The angular velocity of the electron is 4.12\cdot 10^{16} rad/s

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Explanation:

a)

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

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For the electron orbiting around the proton, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

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b)

The period of revolution of the electron is given by

T=\frac{2\pi}{\omega}

where

\omega = 4.12\cdot 10^{16}rad/s is the angular velocity

Substituting,

T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15} rev/s

c)

The centripetal acceleration of an object in circular motion is

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For the electron, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

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a=\frac{(2.18\cdot 10^6)^2}{5.29\cdot 10^{-11}}=8.98\cdot 10^{22} m/s^2

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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