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DiKsa [7]
3 years ago
10

1pt Which is an observation? O A. A person hears the song of a bird. OB. A person suggests that bird calls are a means of commun

ication. O C. A person concludes that bird calls attract mates. OD. A person writes a paper describing different kinds of bird calls....​

Physics
1 answer:
Doss [256]3 years ago
3 0

Answer:

D

Explanation:

he describes as he writes them down

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What must an object have in order to exert a gravitational field?
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Answer:

power

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3 years ago
a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = 100/\pi m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

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4 0
1 year ago
Please help me with the equations for this! Three uniform spheres are fixed at the positions shown in the diagram. ( there is a
lora16 [44]
The change in gravitational potential energy due to change in position must be the change in it's kinetic energy as the system is isolated! so find out the potential energies of the two different points!

<span>PE=−[G<span>M1</span><span>M2</span>]÷R

</span><span> Potential energy of a particle due to mass A is not affected by presence of any other mass B !</span>
7 0
3 years ago
I REALLY NEED HELP WITH PHYSICS ASAP!!!<br>Vf^2 = v0^2 + 2a (xf - x0)<br><br><br>Solve for a
ELEN [110]

Answer:

a. solve for a

vf ^{2} = vo ^{2}  + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2}    -  vo ^{2}   \\ a =  \frac{vf^{2} - vo^{2}  }{2(xf - xo)}    \\ a =  \frac{vf ^{2} - vo ^{2}  }{2xf - 2xo}

I hope I helped you ^_^

7 0
3 years ago
A panda is flying at 3 m/s using a hang-glider. If the panda’s mass is 120 kg and the hang glider’s mass is 50 kg, what is the p
WINSTONCH [101]

Answer:

hmmmmm

Explanation:

(B)

7 0
3 years ago
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