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zysi [14]
4 years ago
5

What disadvantage of convex mirror​

Physics
1 answer:
Eddi Din [679]4 years ago
5 0

Answer:

The disadvantage is that convex mirror is that they make it appear like those objects are at a more noteworthy distance than they actually are. It always gives a virtual, erect and a diminished image.

Explanation:

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A proton of mass mp is released from rest just above the lower plate and reaches the top plate with speed vp. An electron of mas
vodka [1.7K]

Answer:

v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

Explanation:

You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:

F=qE

F_p=F_e

where E is the constant electric field between the parallel plates, and is the same for both electron and proton. Also, the charge is the same.

by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

m_pa_p=qE\\\\a_p=\frac{v_p^2}{2d}\\\\\frac{m_pv_p^2}{2d}=qE

(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

\frac{m_ev_e^2}{2d}=qE

we can equals these expressions for both proton and electron, because the forces qE are the same:

\frac{m_pv_p^2}{2d}=\frac{m_ev_e^2}{2d}\\\\v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

4 0
4 years ago
Find the factor of the number 1.30​
NeX [460]

1 3/10  because 130 is greater than 100 we have simplified this fraction even further to a mixed fraction.

7 0
3 years ago
Read 2 more answers
In the aerials competition in skiing, the competitors speed down a ramp that slopes sharply upward at the end. the sharp upward
ladessa [460]

<u>Answer:</u>

 The skier’s launch speed = 17.08 m/s

<u>Explanation:</u>

The motion of skiing is projectile motion.

 Projectile motion has two types of motion Horizontal and Vertical motion.  

Vertical motion:  

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.  

Considering upward vertical motion of projectile.  

In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g m/s^2 and final velocity = 0 m/s.  

0 = u sin θ - gt  

t = u sin θ/g  

Total time for vertical motion is two times time taken for upward vertical motion of projectile.  

So total travel time of projectile = 2u sin θ/g  

Horizontal motion:  

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.  

In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 m/s^2 and time taken = 2u sin θ /g  

So range of projectile, R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}  

Vertical motion (Maximum height reached, H) :

We have equation of motion, v^2=u^2+2as, where u is the initial velocity, v is the final velocity, s is the displacement and a is the acceleration.  

Initial velocity = vertical component of velocity = u sin θ, acceleration = -g, final velocity = 0 m/s at maximum height H

0^2=(usin\theta) ^2-2gH\\ \\ H=\frac{u^2sin^2\theta}{2g}

We have θ = 63° and H = 11.8 meter.

Substituting

   11.8=\frac{u^2sin^263}{2*9.81}\\ \\ u^2=\frac{11.8*2*9.81}{sin^263}=\frac{231.516}{0.794} =291.58\\ \\ u=17.08m/s

 The skier’s launch speed = 17.08 m/s

3 0
4 years ago
Read 2 more answers
The height of a triangle is 4 in. greater than twice its base. The area of the triangle is no more than 168 in.2. Which inequali
olga2289 [7]

<span>The height (h) of a triangle is 4 in. greater than twice its base (x): h = 2x + 4
</span>The area of the triangle is no more than 168 in.2: A ≤ 168 in²

The area of the triangle is A = x*h/2
Hence x*h/2 ≤ 168 in²

Substitute h in the formula for the area:
h = 2x + 4 = 2(x + 2)
x*h/2 ≤ 168 in²

x * 2(x + 2)/2 ≤ 168
x * (x + 2) ≤ 168
x² + 2x ≤ 168
x² + 2x - 168 ≤ 0

Using the formula for quadratic equation:
x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a} = \frac{-2+/- \sqrt{ 2^{2}-4*1*(-168) } }{2*1}=  \frac{-2+/- \sqrt{ 4+672 } }{2}=  \\  \\ \frac{-2+/- \sqrt{ 676 } }{2}=\frac{-2+/- 26 }{2} \\  \\ &#10;x_1 =  \frac{-2+26}{2} = \frac{24}{2} =12 \\  \\ x_1 =  \frac{-2-26}{2} = \frac{-28}{2} =-14&#10;

6 0
3 years ago
Read 2 more answers
What's the formula for frequency?
Xelga [282]

Answer:

assuming ur speaking about chemistry

c=frequency×wavelength

or

energy=frequency×h

6 0
3 years ago
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