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lubasha [3.4K]
3 years ago
11

An Apple falls from a tree and one-half second later hits the ground

Physics
1 answer:
docker41 [41]3 years ago
8 0
There isnt enough information to answer the question, the missing variable is "distance from said falling spot and ground"
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An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate
riadik2000 [5.3K]

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

4 0
3 years ago
A coin mass 0.005 kg is dropped from a height of 3 m. How much mechanical energy does it have right before it hits the ground ?
lesya692 [45]
Mechanical energy equals the sum of potential and kinetic energy. During the process, all PE converts into KE, assuming air resistance is neglected. So, the mechanical energy does not change and is equal to the initial potential energy.
ME
=mgh
=0.005 x 9.81 x 3
=0.147J
6 0
3 years ago
What are three ways that you know an object has accelerated
ivann1987 [24]

An object has undergone acceleration if ...

-- it's moving faster than it was before
or
-- it's moving slower than it was before
or
-- it's moving in a different direction that it was before.

3 0
3 years ago
1. li took 2 } seconds for a car's vclocity to change from 20 m/s to 15 m/s. The mass of the car was 1370 kg. What force was req
Pani-rosa [81]

Answer:

Do you still need help??

Explanation:

3 0
2 years ago
Starting from rest, the distance a freely-falling object will fall in 0.50 second is?
FinnZ [79.3K]

Answer:

1.23 m

Explanation:

The vertical distance covered by a free-falling object starting from rest in a time t is

y=\frac{1}{2}gt^2

where

g = 9.8 m/s^2 is the acceleration due to gravity

In this problem, we have

t = 0.50 s

So the distance covered is

y=\frac{1}{2}(9.8 m/s^2)(0.50 s)^2=1.23 m

8 0
3 years ago
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