Answer:
Mass, m = 26.54kg
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fapp is the applied force
- Fg is the force due to gravitation
<u>Given the following data;</u>
Net force, Fnet = 345
Acceleration, a = 3.2m/s²
<u>To find mass;</u>
Fnet = Fapp + Fg
Fnet = ma + mg
Fnet = m(a+g)
m = Fnet/(a+g)
We know that acceleration due to gravity, g = 9.8m/s²
Substituting into the equation, we have;
m = 345/(3.2 + 9.8)
m = 345/13
Mass, m = 26.54kg
We have that for the Question it can be said that The maximum height reached by the first <em>object</em> will be 100 times that of the other.
From the question we are told
One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s. The maximum height reached by the first object will be
that of the other.
a. 10,000 times
b. none of these
<em>c. </em><em>1000 times</em>
d. 100 times
<em>e.</em><em> 10 times</em>
Generally the equation for the velocity is mathematically given as
Therefore
The maximum height reached by the first <em>object</em> will be 100 times that of the other.
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Answer:
option C
Explanation:
the ball is moving circular around the pole
Angular momentum of the system is constant
J = I ω
now,
the rope radius is decreasing as it revolving around the pole
angular speed is inversely proportional to radius.
so, the angular speed will increase.
The correct answer is option C
Answer:
The horizontal displacement of the arrow is not larger than the banana split.
Explanation:
Using y - y₀ = ut - 1/2gt², we find the time it takes the arrow to drop to the ground from the top of mount Everest.
So, y₀ = elevation of Mount Everest = 29029 ft = 29029 × 1ft = 29029 × 0.3048 m = 8848.04 m, y = final position of arrow = 0 m, u = initial vertical speed of arrow = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time taken for arrow to fall to the ground.
y - y₀ = ut - 1/2gt²
0 - y₀ = 0 × t - 1/2gt²
-y₀ = -1/2gt²
t² = 2y₀/g
t = √(2y₀/g)
Substituting the values of the variables, we have
t = √(2y₀/g)
= √(2 × 8848.04 m/9.8 m/s²)
= √(17696.08 m/9.8 m/s²)
= √(1805.72 s²)
= 42.5 s
The horizontal distance the arrow moves is thus d = vt where v = maximum firing speed of arrow = 100 m/s and t = 42.5 s
So, d = vt
= 100 m/s × 42.5 s
= 4250 m
= 4.25 km
Since d = 4.25 km < 7.32 km, the horizontal displacement of the arrow is not larger than the banana split.
