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3 years ago

PLEASe HELP!!!!!!!!!!!!! i will give brainliest just pleeeeeesssaasassssszffdtrgfgsthg

Mathematics

1 answer:

postnew [5]3 years ago

5 0

Answer:

7a²/16

Step-by-step explanation:

Area of the triangle PTS

½ × a × a

a²/2

Length of PS:

sqrt(a² + a²)

asqrt(2)

Length of MS:

¼asqrt(2)

Triangles MCS and TPS are similar

With sides in the ratio:

¼asqrt(2) : a

sqrt(2)/4 : 1

Area of triangle SMC:

A/(a²/2) = [(sqrt(2)/4)]²

2A/a² = 1/8

A = a²/16

Area of PTMC

= a²/2 - a²/16

= 7a²/16

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3 years ago

The slope of the line below is -4. Write the equation of the line in point-slope

lapo4ka [179]

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3 years ago

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Sedaia [141]

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6 0

3 years ago

PLEASE HELP

Andru [333]

ANSWER

$q = - 7p$

EXPLANATION

The constant difference of p values is

4-2=2

The constant difference of the 'q' values is

-28--14=-14

The function is of the form:

$q = m(p - p_1) + q_1$

where

$m = \frac{change \: in \:q }{change \: in \: p}$

$m = \frac{ - 14}{2} = - 7$

We plug in the values to get;

$q = - 7(p - 2) + - 14$

Expand:

$q = - 7p + 14+ - 14$

Simplify:

$q = - 7p$

8 0

3 years ago