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3 years ago

PLEASe HELP!!!!!!!!!!!!! i will give brainliest just pleeeeeesssaasassssszffdtrgfgsthg

Mathematics

1 answer:

postnew [5]3 years ago

5 0

Answer:

7a²/16

Step-by-step explanation:

Area of the triangle PTS

½ × a × a

a²/2

Length of PS:

sqrt(a² + a²)

asqrt(2)

Length of MS:

¼asqrt(2)

Triangles MCS and TPS are similar

With sides in the ratio:

¼asqrt(2) : a

sqrt(2)/4 : 1

Area of triangle SMC:

A/(a²/2) = [(sqrt(2)/4)]²

2A/a² = 1/8

A = a²/16

Area of PTMC

= a²/2 - a²/16

= 7a²/16

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3 years ago

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2 years ago

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3 years ago

Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni

dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

$(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})$

It is provided that, Renee recognizes that 7 and $\frac{1}{7}$ are reciprocals, so she would like to find their product before she multiplies by $\frac{13}{29}$ .

The associative property of multiplication states that:

$a\times b\times c=(a\times b)\times c=a\times (b\times c)$

The commutative property of multiplication states that:

$a\times b\times c=a\times c\times b=c\times a\times b$

The distributive property of multiplication states that:

$a\cdot (b+c)=a\cdot b+a\cdot c$

The identity property of multiplication states that:

$a\times 1=a\\b\times 1=b$

So, Renee should use the commutative property of multiplication to find the product of 7 and $\frac{1}{7}$ ,

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Thus, the correct option is commutative property.

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3 years ago

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2 years ago

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