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larisa [96]
3 years ago
11

A coach needs both small and large cones to set up an obstacle course. The coach knows that there are fewer than 30 cones in the

storage room. The coach needs at least a dozen large cones.
Let x represent the number of small cones and y represent the number of large cones.

Which inequalities model the situation? Select each correct answer.
x+y≤30
x>0
x+y<30
y≥12
y>12
Mathematics
2 answers:
jek_recluse [69]3 years ago
6 0

Answer: The correct options are,

x+y < 30

y ≥ 12

Step-by-step explanation:

Here, x represent the number of small cones and y represent the number of large cones.

∵ Large cones are at least 12,

⇒ y ≥ 12,

Now, total cones = x + y

∵ There are fewer than 30 cones,

I.e.  x + y < 30,

Now, number of cones can not be negative,

⇒ x, y ≥ 0

Pepsi [2]3 years ago
5 0
Since they are FEWER than 30 total cones, the sum of x small cones and y large one must be LESS THAN 30: x+y <30
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
y \geqslant 12
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