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3 years ago

Algebra 1 4(x-3)=-16

Mathematics

1 answer:

emmainna [20.7K]3 years ago

8 0

Answer:

x= -1

Step-by-step explanation:

First to whats in the parentheses it will look like this

4x-12=-16 now add 12 to both sides

4x=-4 now you want x alone so divide 4 into -4

x=-1

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1. Your average daily balance on your charge card for the month of July is $855.28. If your card carries an annual interest rate

Nat2105 [25]

1. Using "exact" interest, your charge will be
.. I = Prt
.. I = $855.28*0.154*(31/365)
.. I = $11.19

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.. tax+license + down payment + loan repayment
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3 years ago

Write an equation of the line that passes through the given points.<br> (-1,7) and (4, -8)

djverab [1.8K]

Answer:

y=-3x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-(-1))

m=-15/(4+1)

m=-15/5

m=-3

y-y1=m(x-x1)

y-7=-3(x-(-1))

y-7=-3(x+1)

y=-3x-3+7

y=-3x+4

3 0

3 years ago

PLEASE ANSWER 100 PTS AND WILL MARK BRAINLIEST.

timofeeve [1]

Answer:

Step-by-step explanation:

We have the graph of f(x).

In order to find f(0), we simply need to find the y-coordinate of the coordinate when x is 0.

From the graph, we can see that there is a point at (0,1).

In other words, when x is 0, f(x) is 1.

Therefore:

$f(0)=1$

3 0

3 years ago

Read 2 more answers

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

A bakery sells vanilla cupcakes and chocolate cupcakes. It sold 276 vanilla cupcakes in a day. 8% of the cupcakes sold that day

kkurt [141]

Answer:

hello!!!

300 cupcakes

please read the explanation.. it always helps... trust me...

Step-by-step explanation:

alrighty here it goes...

okay.. so we start by reading the problem (duh) but also underlining the important numbers that we need. yes, it really is that simple, trust me....

okay so the percentage of chocoalte cupcakes was 8% and the amount of vanilla cupcakes was 276.

we start by taking 100% - 8% = 92% so the amount of vanilla cupcakes sold was 276 which is also 92% of the total amount of cupcakes.

so now we need to find out 92% of what number gets us 276.

the percentage formula (in this problem) should be as follows:

92/100 x (total amount of cupcakes) = 276

to solve for total amount of cupcakes you do 276 x 100 then you divide by 92 to get your answer (which is 300)

i hope this helps!!!

4 0

2 years ago